2(x-5)=20
Divide both sides by 2 (division of property equality)
x - 5 = 10
Add 5 to both sides (addition of property equality)
x = 15
Answer
x = 15 is the solution
Well you would just multiply 374 by 15 and that would be your answer
<span>Solving the equation for Y = 1.
5 * (3 * 1 - 2) = 15 * 1 - 10
5 * (3 - 2) = 15 -10
5 * 1 = 5
5 = 5
Solving the equation for Y = 2.
5 * (3 * 2 - 2) = 15 * 2 - 10
5 * (6 - 2) = 30 -10
5 * 4 = 20
20 = 20
Solving the equation for Y = 4.
5 * (3 * 4 - 2) = 15 * 4 - 10
5 * (12 - 2) = 60 -10
5 * 10 = 50
50 = 50
Solving the equation for Y = 8.
5 * (3 * 8 - 2) = 15 * 8 - 10
5 * (24 - 2) = 120 -10
5 * 22 = 110
110 = 110
Solving the equation for Y = 9.
5 * (3 * 9 - 2) = 15 * 9 - 10
5 * (27 - 2) = 135 -10
5 * 25 = 125
125 = 125
This proves that the equation holds good for at least 5 values of 'y', which are 1, 2, 4, 8 and 9.
However, it can be proved that the equation holds good for any value of y.
Expression 5(3y-2) can be simplified to 15y -10 which is the same expression on the right had side of the equation provided.
So, equation 5(3y-2)=15y-10 is actually 15y-10=15y-10 and since this is true for all values of y, it has been proved that it is true for at least 5 values of y.</span>
Answer:
160
Step-by-step explanation:
10% of the candies is 16, and to get 100% from 10% is to multiply by 10.
So 10% *10 = 100%, then by association if 16 = 10%, then 16*10 will be the total 100%.
Hii!
So I did this and I have A!
A: You cannot get the mean from the graph but you CAN get the third quartile!
B: To find the interquartile range (IQR) we subtract the third and first quartiles:
60-35 = 25
C: An outlier would be much larger than the rest of the data or much smaller than the rest of the data. An outlier would make the "whisker" portion longer and could potentially slightly shift the box.