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soldier1979 [14.2K]
2 years ago
15

Halp me please, 10 points! ASAP

Mathematics
2 answers:
serg [7]2 years ago
7 0
I think the answer could be two.
erastovalidia [21]2 years ago
5 0
I cannot see the numbers but i am guessing it is 2 since its in the negative region
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The base of a solid is bounded by the curve y = sqrt (x+1) the x-axis and the line x = 1. the cross sections, taken perpendicula
Andrei [34K]

See attached for a sketch of some of the cross sections.

Each cross section has area equal to the square of the side length, which in turn is the vertical distance between the curve y = √(x + 1) and the x-axis (i.e. the distance between them that is parallel to the y-axis). This distance will be √(x + 1).

If the thickness of each cross section is ∆x, then the volume of each cross section is

∆V = (√(x + 1))² ∆x = (x + 1) ∆x

As we let ∆x approach 0 and take infinitely many such cross sections, the total volume of the solid is given by the definite integral,

\displaystyle \int_{-1}^1 (x+1) \, dx = \left(\frac{x^2}2 + x\right) \bigg|_{-1}^1 = \boxed{2} ~~~~ (B)

3 0
2 years ago
PLEASE HELP ME PLEASE PLEASE
mezya [45]
1)

Break up the irregular shape into two rectangles

12 * 4.5 = 54
2 * 5 = 10
54 + 10 = 64 cm^2

2)

Break up the irregular shape into a triangle and rectangle

24 * 8 = 192

To get the base of the triangle:
24 - 6 - 6 = 12
To get the height of the triangle:
16 - 8 = 8

1/2(12 * 8) = 48

192 + 48 = 240 yd^2

3)

Separate into triangle and semi circle

To get the base: 8 * 2 = 16

1/2(15 * 16) = 120

(pi (8)^2)/2 = 100.5

120 + 100.5 = 220.5 cm^2

4)

Separate half circle from rectangle

(pi (7.5)^2)/2 = 88.4

7 * 15 = 105

88.4 + 105 = 193.4 m^2

5)

Separate triangle from trapezoid

2.8 * 7 = 19.6

(7+9/2)(3.6) = 28.8

19.6 + 28.8 = 48.4 ft^2

6)

Separate semi circle from trapezoid

(pi(3)^2)/2 = 6.3

(6+10/2)(8) = 64

6.3 + 64 = 70.3 yd^2

8 0
2 years ago
Inputs are represented by the variable x .<br><br><br> True or False
NNADVOKAT [17]

Answer:

true

Step-by-step explanation:

4 0
2 years ago
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Tan^2x+sec^2x=1 for all values of x. <br> true or false?
amid [387]

This is not true.

\tan^2x+\sec^2x=\dfrac{\sin^2x}{\cos^2x}+\dfrac1{\cos^2x}=\dfrac{1-\cos^2x+1}{\cos^2x}=2\sec^2x-1

2\sec^2x-1=1\implies\sec^2x=1\implies\sec x=\pm1\implies x=n\pi

where is n is any integer. So suppose we pick some value of x other than these, say x=\dfrac\pi4. Then

\tan^2\dfrac\pi4+\sec^2\dfrac\pi4=1+2=3\neq1

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Does anybbody know the answer to this? #help
Gwar [14]

Answer:

each tube costs $1.5 so put it the point in between 1 and 2

thank you

Step-by-step explanation:

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2 years ago
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