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LiRa [457]
3 years ago
7

A company began a new development project in 2017. The project reached technological feasibility on June 30, 2018, and was avail

able for release to customers at the beginning of 2019. Development costs incurred prior to June 30, 2018, were $3,800,000 and costs incurred from June 30 to the product release date were $2,150,000. The 2019 revenues from the sale of the new software were $4,000,000, and the company anticipates additional revenues of $6,500,000. The economic life of the software is estimated at four years. Amortization of the software development costs for the year 2019 would be:
Business
1 answer:
o-na [289]3 years ago
8 0

Answer:

$818,935

Explanation:

Percentage of-revenue method:

$4,000,000

($4,000,000 + 6,500,000) = $10,500,000

Hence;

$4,000,000/$10,500,000

= 38.09 %

Amortization = 38.09% ×$2,150,000

= $818,935

Therefore the amortization of the software development costs would be $818,935

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If a car company sold a vehicle for $50000 and was produced by 10000 what is the profit?
expeople1 [14]

Answer:

$ 40,000

Explanation:

profits are obatined by substracting toatl expenses from total revenues.

i.e profits= Total revenue - total costs

   

in this case: cost of production = $ 10,000.00

                    selling price           = $ 50,000.00

profits= $50,000-$ 10,000= $ 40,000

6 0
3 years ago
The number of persons coming through a blood bank until the first person with type A blood is a random variable Y with a geometr
GenaCL600 [577]

Answer:

a. ½(Y² - Y) is an unbiased estimator of the variance.

b. 2 Standard Error = 2√(Y²/2 - Y/2)

Explanation:

Given

E(Y) = 1/p

V(Y) = (1 - p)/p²

Simplifying V(Y)...

V(Y) = 1/p² - 1/p

Because V(Y) = 1/p² - 1/p and E(Y) = 1/p,

We'll guess that there might be an unbiased estimator of shape

aY² + bY.

Solving E(aY² + bY)...

First, E(Y²) = V(Y) + (E(Y))²

Substituting the values of V(Y) and E(Y);

E(Y²) = 1/p² - 1/p + (1/p)²

E(Y²) = 1/p² - 1/p + 1/p²

E(Y²) = 2/p² - 1/p

With the above,

E(aY² + bY) is then equal to

E(aY² + bY) = 2a/p² - a/p + b/p

The above equation is equal to V(Y), if and only if

a = ½ and b = -½

-------------- Checking------------

Let E(aY² + bY) = V(Y)

i.e.

2a/p² - a/p + b/p = 1/p² - 1/p

Multiply through by l

2a/p - a + b = 1/p - 1

Comparing right hand side to left hand side

2a/p = 1/p ----- Equation 1

And

- a + b = - 1 ------- Equation 2

Solving Equation 1 (Multiply both sides by p)

2a = 1

So, a = ½

Substitute ½ for a in Equation 2

-½ + b = -1

b = -1 + ½

b = -½

------------ End --------------

Thus ½(Y² - Y) is an unbiased estimator of the variance.

b.

2 Standard Error is given by

2√V(Y)

= 2√(1/p² - 1/p)

= 2√(Y²/2 - Y/2)

6 0
3 years ago
| 50 POINTS | If The Oil Prices Around The World Rise , What Will Happen To The Oil Production In Texas?
timofeeve [1]
The oil will increase in texas
5 0
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Answer:

Explanation:

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