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matrenka [14]
3 years ago
15

A bag contains 28 blue marbles and 12 red marbles. If Milton removes two marbles without replacing them, what is the probability

that the first marble will be blue and the second one will be red?
Mathematics
1 answer:
Daniel [21]3 years ago
4 0
The probability the first marble will be blue is 28/40 
The probability the second marble will be red is 12/39 
The reason is because 28 + 12 = 40, so this makes the denominator for our first outcome, but then a marble is removed making our denominator 39 because 40-1 = 39. 
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Can anyone help? I’d greatly appreciate it :)
Lena [83]

Answer:

bilmiyorum sna kolu gelsın

8 0
3 years ago
The ratio of the side lengths of a quadrilateral is 3:3:5:8, and the perimeter is 380cm. What is the measure of the longest side
castortr0y [4]

Answer:

160

Step-by-step explanation:

Add the ratios together to get the sum of them is 19.  Since the perimeter is 380, divide 380 by 19 to get 20.  

The shortest side is 3(20) = 60,

the next side is 5(20) = 100, and

the longest side is 8(20) = 160

3 0
3 years ago
What is the area of a sector with a central angle of 2pi/9 radians and a diameter of 20.6mm? Use 3.14 for Ali and round your ans
LuckyWell [14K]
- The area of the circle is:

 A=πr²

 A is the area of the circle.
 π=3.14
 r is the radius of the circle.

 - To calculate the area of <span> the sector indicated in the problem, you must apply the following formula:

 As=(</span>θ/2π)πr²

 As is the area of the sector.
 θ is the central angle (θ=2π/9)
 π=3.14
 r is the radius.

 - First, you must find the radius:

 r=Diameter/2
 r=20.6 mm/2
 r=10.3 mm

 - Now, you can substitute the values into the formula As=(θ/2π)πr². Then, you have:

 As=(θ/2π)πr²
 As=(2π/9/2π)(π)(10.3)²
 As=(π/9π)(π)(10.3)²
 As=(3.14/9x3.14)(3.14)(10.3)²

 - Finally, the area of the sector is:

 As= 37.01 mm²
6 0
3 years ago
Read 2 more answers
4 Consider the triangle below.
Maurinko [17]
<h2>=>> <u>Solution (part A</u>) :</h2>

Given :

▪︎Triangle AMG is an isosceles triangle.

▪︎Measure of segment AM = (x+1.4) inches

▪︎Measure of segment MG = (2x+0.1) inches

▪︎Measure of segment AG = (3x-0.4) inches

▪︎segment AG is the base of triangle AMG.

Since AG is the base of the isosceles triangle AMG, segment AM and segment MG will be equal.

Which means :

= \tt x + 1.4 = 2x + 0.1

= \tt x + 1.4 - 0.1 = 2x

=  \tt \: x + 1.3 = 2x

= \tt 1.3 = 2x - x

\color{plum} \hookrightarrow  \tt x = 1.3

Thus, the value of x = 1.3

Therefore :

▪︎The value of x = 1.3

<h2>=>> <u>Solution (Part B)</u> :</h2>

We know that :

▪︎The value of x = 1.3

Which means :

The length of the leg AM :

= \tt x + 1.4

= \tt 1.3 + 1.4

\color{plum} \tt leg \: AM= 2.7 \: inches

Thus, the length of the leg AM = 2.7 inches

The length of leg MG :

= \tt 2x + 0.1

=  \tt2 \times 1.3 + 0.1

= \tt 2.6 + 0.1

\color{plum} \tt\: leg \:MG = 2.7 \: inches

Thus, the length of the leg MG = 2.7 inches

Since the measure of the two legs are equal (2.7=2.7), we can conclude that we have found out the correct length of each leg.

Therefore :

▪︎Measure of leg AM = 2.7 inches

▪︎Measure of leg MG = 2.7 inches

<h2>=>> <u>Solution </u><u>(</u><u>part C</u><u>)</u> :</h2>

We know that :

Value of x = 1.3

Then, measure of the base AG :

=  \tt 3x - 0.4

= \tt 3 \times 1.3 - 0.4

= \tt 3.9 - 0.4

\color{plum}\tt \: Base  \: AG = 3.5 \:  inches

Thus, the measure of the base = 3.5 inches

Therefore :

▪︎ the length of base AG = 3.5 inches.

6 0
3 years ago
Solve the inequality
const2013 [10]
X < -11/9 is the answer

4 0
3 years ago
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