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alexandr402 [8]

3 years ago

12

Eff traveled at an average speed of 65 miles per hour for 2.5 hours and then traveled at an average speed of 70 miles per hour f

or 1.5 hours. What was the total distance in miles that Jeff traveled during this time?
A. 272.5 miles
A. 272.5 miles

B. 267.5 miles
B. , 267.5 miles,

C. 270 miles
C. 270 miles

D. 337 miles

1 answer:

AleksandrR [38]3 years ago

3 0

Answer:

267.5 miles

Step-by-step explanation

65×2.5=162.5

70×1.5=105

162.5+105=267.5

<h2> 267.5</h2>

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Answer:

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Step-by-step explanation:

Given the expression

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$

$=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$ ∵ $\frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}$

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$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

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$=-\frac{3}{20}$

Therefore,

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Question # 2

Answer:

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

Step-by-step explanation:

Given

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}$

$=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}$ ∵ $\frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}$

$=-\frac{6}{35}-\frac{1}{140}$ ∵ $\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}$

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$=-\frac{5}{28}$

Therefore,

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