Answer:
v = 1/(1+i)
PV(T) = x(v + v^2 + ... + v^n) = x(1 - v^n)/i = 493
PV(G) = 3x[v + v^2 + ... + v^(2n)] = 3x[1 - v^(2n)]/i = 2748
PV(G)/PV(T) = 2748/493
{3x[1 - v^(2n)]/i}/{x(1 - v^n)/i} = 2748/493
3[1-v^(2n)]/(1-v^n) = 2748/493
Since v^(2n) = (v^n)^2 then 1 - v^(2n) = (1 - v^n)(1 + v^n)
3(1 + v^n) = 2748/493
1 + v^n = 2748/1479
v^n = 1269/1479 ~ 0.858
Step-by-step explanation:
Answer:
i belive it is answer B
Step-by-step explanation:
7 and 7/28 I think if I did that right
Answer:
Step-by-step explanation:
First get the answer to -3n - 4 = 2
-3n - 4 + 4 = 2 + 4
-3n = 6
n = 6/-3
n = -2
That answer is the only one that is permitted. It is the only one that completely satisfies the equation.
Now when you do the inequality, look what happens.
-3n - 4 < 2 Add 4 to both sides.
-3n-4+ 4 < 2+4
-3n < 6 Now there are a bunch of ways (2) to solve this.
No matter which way you do it, the arrow will change.
-3n/-3 > 6/-3
n > - 2
That means that any number that is greater than - 2 will satisfy the inequality.
So n = 0 will work. Even n = - 1 will work. Anything bigger than -2 will work. The equation does not provide that kind of latitude.
