Y’’(x)= 6x + 1
y’(x)= 3x^2 + x + 2
y(x)= x^3 + 1/2x^2 + 2x + 5
ANSWER
1.39
EXPLANATION
The given quadratic equation is
This is the same as,
Comparing to
We have
a=2, b=3,c=-8
Using the quadratic formula, the solution is given by:
We substitute the values to get,
The positive root is
to the nearest hundredth.
let us take any two points here (5,20) and (7,30)
now let us use slope formula to get its slope
slope =5
now let us use one coordinate (say (5,20)) and slope to get the y intercept
20= 5*5 +b
b=-5
plugging the values of b and m in the given equation we get
y=5x-5
or c=5m-5