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3 years ago

Solve for x Find ADB Find BDC

Mathematics

1 answer:

NeTakaya3 years ago

5 0

Answer:

x=12 ADB= 56 BDC= 54

Step-by-step explanation:

ADB and BDC are complementary, so they add up to 90 degrees. In other words ADB+BDC= 90 So I can input my knowns into the equation

(3x+10) + (4x-4) = 90

I combined like terms to give me 7x+6=90

Then I subtract 6 from both sides giving me 7x=84

Last I divide 7 on both sides. x=12

Then I input the x (12) into the equation and solve it from there

3(12)+10 and 4(12)-4

3(12)+10=56

4(12)-4=54

. . . I think. Hope this helps!

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Find the perimeter of quadrilateral ABCD with vertices A(-2,-2), B(-1,3),

drek231 [11]

Answer:

Step-by-step explanation:

Step one

given the coordinates

ABCD with vertices A(-2,-2), B(-1,3), C(5, 3), and D(4, -2)

AB=(-2,-2),(-1,3)

BC=(-1,3), (5, 3)

CD=(5, 3),(4, -2)

DA=(4, -2),(-2,-2)

The distance between points AB=

$AB= \sqrt (x_2-x_1)^2+(y_2-y_1)^2$

$AB= \sqrt (-1+2)^2+(3+2)^2\\\\AB= \sqrt 1^2+(5)^2\\\\AB= \sqrt26\\\\AB=5.1$

The distance between points BC=

$BC= \sqrt (5+1)^2+(3-3)^2\\\\BC= \sqrt 6^2+(0)^2\\\\BC= \sqrt36\\\\BC=6$

The distance between points CD

$CD= \sqrt (4-5)^2+(-2-3)^2\\\\CD= \sqrt -1^2+(-5)^2\\\\CD= \sqrt26\\\\CD=5.1$

The distance between points DA

$DA= \sqrt (4+2)^2+(-2+2)^2\\\\DA= \sqrt 6^2+(0)^2\\\\DA= \sqrt36\\\\DA=6$

Hence the perimeter = 5.1+6+5.1+6

= 22.2

5 0

3 years ago

Can you help me please (get brainliest)

marta [7]

9514 1404 393

Answer:

4/25

Step-by-step explanation:

Put the numbers where the letters are and do the arithmetic.

$\left(2\cdot\dfrac{-1}{2}\cdot\dfrac{2}{5}\right)^2=\left(\dfrac{-2}{5}\right)^2=\dfrac{(-2)^2}{5^2}=\boxed{\dfrac{4}{25}}$

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3 years ago

Simplify the ratio 70lbs to 42lbs to lowest terms

Anit [1.1K]

Simplify by dividing the two by 14

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4 years ago

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3 years ago

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guajiro [1.7K]

Answer:

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Step-by-step explanation:

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3 years ago