Question

Force6x + 8 " alt=" {x }^{2} + 6x + 8 " align="absmiddle" class="latex-formula">
​

Answer 1

Answer:

x=-2,-4 is your answer

x²+6x+8=0

doing middle term factorization

x²+4x+2x+8=0

x(x+4)+2(x+4)=0

(x+4)(x+2)=0

either

x=-4

or

x=-2

Answer 2

Step-by-step explanation:

❁ $\underline{ \underline{ \large{\tt{T \: O \: \: F \: A \: C \: T \: O \: R \: I\: Z \: E \: }}}} :$

• $\large{ \tt{ {x}^{2} + 6x + 8}}$

❁ $\underline{ \underline{ \large { \tt{S \: O \: L \: U \: T \: I \: O \: N}} }} :$

Firstly find two numbers which when multiplied results to 8 and when added,it results to 6. The two numbers must be 4 and 2.

⟶ $\large{ \tt{ {x}^{2} + (4 + 2)x + 8}}$

⟶ $\large{ \tt{ \underbrace{{x}^{2} + 4x} + \underbrace{2x + 8}}}$

Now, Take common from first two terms :

⟶ $\large {\tt{x(x + 4) + 2x + 8}}$

Take common from last two terms :

⟶ $\large{ \tt{x(x + 4) + 2(x + 4)}}$

⟶ $\large{ \tt{(x + 4)(x + 2)}}$

⟿ $\boxed{ \boxed{ \underline{ \text{Our \: Final \: Answer : \boxed{ \bold{ \text{(x + 4)(x + 2)}}}}}}}$

Hope I helped ! ツ

Have a wonderful day / night ! ♡

✧ $\underline{ \underline{ \mathfrak{Carry \: on \: learning}}}$ !! ✎

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