We are given with an 18 student class that is working a project worked by pairs. Each pair works on a project. In this case, there are 9 teams of 2 individuals working on a single project. Hence for a year or school year, there are 9 projects accomplished each time.
Using it's concept, it is found that the domain for the expressions is, respectively, given by:
<h3>What is the domain of a function?</h3>
It is the <u>set that contains all possible input values</u>.
In a fraction, the denominator cannot be zero, hence:
- The domain of the first two expressions is of
.
- The domain of the last expression is of
.
The third expression can be simplified, as:
(x + 5)/(x + 5) = 1.
The same is true for the fourth, as:
x²/x = 1.
Neither has any restriction, hence their domain is all real numbers, represented by 
.
More can be learned about the domain of a function at brainly.com/question/25897115
Answer:
Step-by-step explanation:
You need the Pythagorean Theorem to solve this question. There is no be part.
Equation
c^2 = a^2 + b^2
Givens
a = 32
b = 21
c = ?
Solution
c^2 = a^2 + b^2 Substitute the values
c^2 = 32^2 + 21^2 Expand
c^2 = 1024 + 441 Combine
c^2 = 1465 Take the square root of both sides
√c^2 = √1465
c = 38.275
Answer: 38.3 rounded
It can be written as √64·√x¹⁶ = 8x⁸, so answer B.
Start by putting two coins on each side of the scale. If one side is higher, then the light coin must be in that pair (use a second weighing to determine which of that pair is the lightest.)
If the initial weighing shows the two pairs to be even, discard those four and go to the three others. Put two of the coins on the scale - one on each side. If one side stays higher, that coin is your light one. If however they are equal, the final unweighed coin must be the lighter coin.
