Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
12.74 divided by 13 is 0.98.
Hope that helped:)
Answer:
r = -0.0056 --> 5.6%
Step-by-step explanation:
The third one its already in order
Answer:
Step-by-step explanation:
Given
Required
PQ
Since Q is between the given points, then:
This gives:
Collect like terms
Next, solve for x
We have:
This gives:
Collect like terms
Divide by 2
So:
