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babunello [35]
3 years ago
12

Use the relationship between the angles in the figure to answer

Mathematics
2 answers:
Wewaii [24]3 years ago
7 0

Answer:

=180-31+40

=180-71

=109

Sholpan [36]3 years ago
5 0
31+40 = 71. 180-71=109
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12
AveGali [126]

The rise/run of AC and CE in the similar triangles are the same, the true statement is: B. slope of AC = slope of CE.

<h3>What is the Slope of the Sides of Similar Triangles?</h3>

On a coordinate plane, the corresponding sides of two triangles are always the same because the ratio of the rise over run is always the same.

Triangles ABC and CDE are similar triangles, therefore the rise over run of AC and CE, which is the slope, will be the same.

Thus, slope of AC = slope of CE.

Learn more about slope on:

brainly.com/question/3493733

7 0
2 years ago
Joyce is helping to make wreaths for her Women’s Club to sell at a local bazaar. She will be making the bows for each wreath. Sh
jok3333 [9.3K]

Answer:

She can make 34 bows with 10 feet of ribbon left

Step-by-step explanation:

1.5x34=51

61-51=10 feet of ribbons left

51/1.5=x

4 0
3 years ago
Please help I been here for I hour
jok3333 [9.3K]
9 mph because if it was 4/5 miles in 1/10 of an hour you just multiply it by 10 to get an hour and if you multiply 4/5 x 10 equals 40/5. simplified it is 9
3 0
3 years ago
Read 2 more answers
Assume we need to estimate the mean of a normally-distributed population with great accuracy. Specifically, for significance lev
bulgar [2K]

Answer:

n = 2662.56\sigma^2                                

Step-by-step explanation:

We are given the following in the question:

Significance level = 0.01

Width of interval = 0.1

Population variance = \sigma^2

We have to find the sample size so that the width of the confidence interval is no larger than 0.1

z_{critical}\text{ at}~\alpha_{0.01} = \pm 2.58

Formula for sample size:

n = \displaystyle\frac{z^2\sigma^2}{E^2}

where E is the margin of error. Since the confidence interval width is 0.1,

E = 0.05

Putting these values in the equation:

n = \displaystyle\frac{(2.58)^2\sigma^2}{(0.05)^2} = 2662.56\sigma^2

So, the above expression helps us to calculate the sample size so that the width of the confidence interval is no larger than 0.1 for different sample variances.

4 0
4 years ago
Please help, I don’t understand this at all..
kkurt [141]
Answer: 120

Explanation






6 0
3 years ago
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