Answer: 
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
 
        
             
        
        
        
12.74 divided by 13 is 0.98. 
Hope that helped:)
        
                    
             
        
        
        
Answer:
r = -0.0056 --> 5.6%
Step-by-step explanation:
 
        
             
        
        
        
The third one its already in order
        
             
        
        
        
Answer:

Step-by-step explanation:
Given



Required
PQ
Since Q is between the given points, then:

This gives:

Collect like terms


Next, solve for x
We have:


This gives:

Collect like terms


Divide by 2

So:


