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masha68 [24]
3 years ago
8

What is the value of x

Mathematics
2 answers:
Rina8888 [55]3 years ago
3 0
The angles are congruent because they are vertical so we can set them equal to one another.

3x + 50 = 6x - 10
3x + 60 = 6x
60 = 3x
20 = x
scoundrel [369]3 years ago
3 0
If I'm correct your equation is
3x+50=<span>6x−<span>10
</span></span>Now we solve it
---------------
Subtract 6x from each side
<span>3x+50−6x</span>=<span>6x−10−<span>6x
</span></span><span>−3x+50</span>=<span>−<span>10
</span></span>--------------------
Subtract 50 from each side
<span><span><span>−3x</span>+50</span>−50</span>=−10−<span>50
</span>-3x = -60
-----------------------
Divide each side by -3
-3x ÷ -3 = -60 ÷ -3
x = 20
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Romashka-Z-Leto [24]
Square prism

because of the two squares on the side and it’s a prism not a pyramid because it just isn’t lol
8 0
3 years ago
A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be
irga5000 [103]

Answer:

The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

Step-by-step explanation:

Let C = (h,k) the coordinates of the center of the circle, which must be transformed into C'=(h', k') by operations of translation and reflection. From Analytical Geometry we understand that circles are represented by the following equation:

(x-h)^{2}+(y-k)^{2} = r^{2}

Where r is the radius of the circle, which remains unchanged in every operation.

Now we proceed to describe the series of operations:

1) <em>Center of the circle is translated 4 units to the right</em> (+x direction):

C''(x,y) = C(x, y) + U(x,y) (Eq. 1)

Where U(x,y) is the translation vector, dimensionless.

If we know that C(x, y) = (h,k) and U(x,y) = (4, 0), then:

C''(x,y) = (h,k)+(4,0)

C''(x,y) =(h+4,k)

2) <em>Reflection over the x-axis</em>:

C'(x,y) = O(x,y) - [C''(x,y)-O(x,y)] (Eq. 2)

Where O(x,y) is the reflection point, dimensionless.

If we know that O(x,y) = (h+4,0) and C''(x,y) =(h+4,k), the new point is:

C'(x,y) = (h+4,0)-[(h+4,k)-(h+4,0)]

C'(x,y) = (h+4, 0)-(0,k)

C'(x,y) = (h+4, -k)

And thus, h' = h+4 and k' = -k. The statement is now presented as:

\exists\, (h,k)\in \mathbb{R}^{2} /f: (x-h^{2})+(y-k)^{2}=r^{2}\implies f': [x-(h+4)]^{2}+[y-(-k)]^{2} = r^{2}

In other words, this mathematical statement can be translated as:

<em>There is a point (h, k) in the set of real ordered pairs so that a circumference centered at (h,k) and with a radius r implies a equivalent circumference centered at (h+4,-k) and with a radius r. </em>

<em />

4 0
3 years ago
Determine the coefficient matrix of the system of equations latex: 3x-2y = 7,\; x+4y=2. 3 x − 2 y = 7 , x + 4 y = 2. what is the
Amanda [17]

When put in matrix form, the coefficients of

... 3x -2y = 7

... x + 4y = 2


look like


\left[\begin{array}{cc}3&-2\\1&4\end{array}\right]


The determinant is 3×4 - 1×(-2) = 14.

4 0
4 years ago
Write down the equation for the following
Mice21 [21]
Grade 7 got total 88 books
No. Of books given on Friday = 63
No. Of books on Tuesday =g
g = 88 - 63
g = 25
5 0
2 years ago
What are the possible values of remainder r, when a positive integer 'a' is divided by 3​
fredd [130]

Answer:

0, 1, 2

Step-by-step explanation:

Euclid's division Lemma states that for any two positive integers ‘a’ and ‘b’ there exist two unique whole numbers ‘q’ and ‘r’ such that , a = bq + r, where 0≤ r < b.

Here, a= Dividend, b= Divisor, q= quotient and r = Remainder.

According to Euclid's division lemma a 3q+r, where 0≤r≤3 and r is an integer.

Therefore, the values of r can be 0, 1 or 2.

6 0
3 years ago
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