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3 years ago

8

Dorothy put $470 into a savings account for one year. The rate of interest on the account was 5.5%. Find the interest earned on

the amount.
A. $27.75
B. $26.50
C. $28.25
D. $25.85

1 answer:

Rama09 [41]3 years ago

6 0

Answer:

D. $25.85

Step-by-step explanation:

470 x 5.5% = 25.85

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Can someone show me how to factor this please?

Alex_Xolod [135]

Answer:

$\displaystyle \theta = \left\{\frac{7\pi}{6}, \, \frac{3\pi}{2}, \frac{11\pi}{6}\right\}$

Step-by-step explanation:

We want to solve the equation:

$2\sin ^2 \theta + 3\sin \theta + 1 = 0$

In the interval [0, 2π).

Notice that this is in quadratic form. Namely, by letting u = sin(θ), we acquire:

$\displaystyle 2u^2 + 3u + 1 = 0$

Factor:

$\displaystyle (2u+1)(u+1) = 0$

By the Zero Product Property:

$\displaystyle 2u + 1 = 0\text{ or } u + 1 = 0$

Solve for each case:

$\displaystyle u = -\frac{1}{2} \text{ or } u = -1$

Back-substitute:

$\displaystyle \sin \theta = -\frac{1}{2} \text{ or } \sin \theta =-1$

Use the Unit Circle. Hence, our three solutions in the interval [0, 2π) are:

$\displaystyle \theta = \left\{\frac{7\pi}{6}, \, \frac{3\pi}{2}, \frac{11\pi}{6}\right\}$

8 0

3 years ago

What is the range of the following function:<br> y = 2(5^x) - 1

Orlov [11]

<h2>Hello!</h2>

The answer is:

The range of the function is:

Range: y>2

or

Range: (2,∞+)

<h2>Why?</h2>

To calculate the range of the following function (exponential function) we need to perform the following steps:

First: Find the value of "x"

So, finding "x" we have:

$y=2(5^{x}-1)\\\frac{y}{2}=5^{x}-1\\\\\frac{y}{2}-1=5^{x}\\\\Log_{5}(\frac{y}{2}-1)=Log_5(5^{x})\\\\x=Log_{5}(\frac{y}{2}-1)$

Second: Interpret the restriction of the function:

Since we are working with logarithms, we know that the only restriction that we found is that the logarithmic functions exist only from 0 to the possitive infinite without considering the number 1.

So, we can see that if the variable "x" is a real number, "y" must be greater than 2 because if it's equal to 2 the expression inside the logarithm will tend to 0, and since the logarithm of 0 does not exist in the real numbers, the variable "x" would not be equal to a real number.

Hence, the range of the function is:

Range: y>2

or

Range: (2,∞+)

Note: I have attached a picture (the graph of the function) for better understanding.

Have a nice day!

5 0

3 years ago

How to solve 3x^2+22x=-35 by factoring

Zepler [3.9K]

Answer:

x = -7/3 or -5

Step-by-step explanation:

3x^2 + 22x = -35

3x^2 + 22x + 35 = 0

(3x + 7) (x + 5) = 0

so for 3x+7:

3x+7 = 0

3x = -7

x = -7/3

So for x + 5:

x + 5 = 0

x = -5

3 0

3 years ago

To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in

lukranit [14]

Answer: $\dfrac{26}{27}$

Step-by-step explanation:

Given : To avoid detection at customs, a traveler places 6 narcotic tablets in a bottle containing 9 vitamin tablets that are similar in appearance.

Proportion of success : $p=\dfrac{6}{9}=\dfrac{2}{3}$

Sample size taken by customs oﬃcial : n= 3

Let x be a binomial variable that represents the tablets in the bottle.

Using Binomial probability formula :-

$P(X=x)=^nC_xp^x(1-p)^{n-x}$

The probability that the traveler will be arrested for illegal possession of narcotics = $P(x\geq1)=1-P(x=0)$

$1-^3C_0(\dfrac{2}{3})^0(1-\dfrac{2}{3})^3\\\\=1-(1)(1)(\dfrac{1}{3})^3\ [\becuase ^nC_0=1]\\\\=1-\dfrac{1}{27}=\dfrac{26}{27}$

Hence, the probability that the traveler will be arrested for illegal possession of narcotics = $\dfrac{26}{27}$

8 0

4 years ago

A $16,000 robot depreciates linearly to zero in 10 years. (a) find a formula for its value as a function of time, t, in years.

SVETLANKA909090 [29]

We are given, cost of the robot for 0 number of year = $16,000.

0 represents initial time of the robot.

After 10 year cost of the robot is = $0

The problem is about the number of the years and cost of the robot over different number of years.

So, we could take x coordinate by number of hours and y coordinate for y number of hours.

So, from the problem, we could make two coordinates for the given situation.

(x1,y1) = (0, 16000) and (x2,y2) = (10, 0).

In order to find the function of time, we need to find the rate at which robot rate depreciates each year.

Slope is the rate of change.

So, we need to find the slope of the two coordinates we wrote above.

We know, slope formula

$Slope (m) = \frac{y2-y1}{x2-x1}$

Plugging values in formula, we get

$m=\frac{0-16000}{10-0} = \frac{-16000}{-10} = -1600.$

Brecasue of depreciation we got a negative number for slope or rate of change.

Therefore, rate of depreciation is $1600 per year.

We already given inital cost, that is $16,000.

So, we can setup an a function

f(x) = -1600x + 16000.

But the problem is asked to take the variable t for time.

Replacing x by t, we get

f(t) = -1600t + 16000.

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3 years ago