The time required to get a total amount of $13,200.00 with compounded interest on a principal of $7,000.00 at an interest rate of 5.5% per year and compounded 12 times per year is 11.559 years. (about 11 years 7 months)
Answer:
t = 11.559 years
<h3>Compound Interest </h3>
Given Data
(about 11 years 7 months)
Calculation Steps:
First, convert R as a percent to r as a decimal
r = R/100
r = 5.5/100
r = 0.055 per year,
Then, solve the equation for t
t = ln(A/P) / n[ln(1 + r/n)]
t = ln(13,200.00/7,000.00) / ( 12 × [ln(1 + 0.055/12)] )
t = ln(13,200.00/7,000.00) / ( 12 × [ln(1 + 0.0045833333333333)] )
t = 11.559 years
Learn more about compound interest here:
brainly.com/question/24924853
We want to solve the Initial Value Problem y' = y + 4xy, with y(0) = 1.
To use Euler's method, define
y(i+1) = y(i) + hy'(i), for i=0,1,2, ...,
where
h = 0.1, the step size.,
x(i) = i*h
1st step.
y(0) = 1 (given) and x(0) = 0.
y(1) ≡ y(0.1) = y(0) + h*[4*x(0)*y(0)] = 1
2nd step.
x(1) = 0.1
y(2) ≡ y(0.2) = y(1) + h*[4*x(1)*y(1)] = 1 + 0.1*(4*0.1*1) = 1.04
3rd step.
x(2) = 0.2
y(3) ≡ y(0.3) = y(2) + h*[4*x(2)*y(2)] = 1.04 + 0.1*(4*0.2*1.04) = 1.1232
4th step.
x(3) = 0.3
y(4) ≡ y(0.4) = y(3) + h*[4*x(3)*y(3)] = 1.1232 + 0.1*(4*0.3*1.1232) = 1.258
5th step.
x(4) = 0.4
y(5) ≡ y(0.5) = y(4) + h*[4*x(4)*y(4)] = 1.258 + 0.1*(4*0.4*1.258) = 1.4593
Answer: y(0.5) = 1.4593
What you do is you rearrange and simplify both equations to have them in terms of y, and then graph them. If it asked for a solution, their point of intersection would be the solution.
Answer:
192
Step-by-step explanation:
Given
4xyz ← substitute given values into expression
= 4 × - 2 × - 6 × 4 = - 8 × - 24 = 192
