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3 years ago

Suppose you roll two die. Find the number of elements in the event space of rolling a sum of 5. A. 3 B. 4 C. 5 D. 6

Mathematics

1 answer:

DedPeter [7]3 years ago

6 0

ANSWER

B. 4

EXPLANATION

The numbers on the first die are;

{1,2,3,4,5,6}

The numbers on the second die are;

{1,2,3,4,5,6}

The events of getting a sum of 5 are

2+3

3+2

1+4

4+1

There are four events.

The correct choice is B .

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A sheet metal manufacturer is making 10-gauge sheet metal, which is supposed to be 3.416 mm thick. One of the pieces of manufact

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Answer:

Step-by-step explanation:

We need to evaluate if thickness of a 10 gauge metal sheet is a requiered in the process that means 3.416 mm thick. So that should be our null hypothesis; μ₀ = 3.416 and based on sample data, we will formulate an alternative hypothesis taking into account the mean, and standard deviation obtained. We surely will have better information to take a decision

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3 years ago

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

6 0

3 years ago

PAGE 6

Ann [662]

a) A mathematical equation that represents the total cost, t, for a adult tickets and c child tickets is t = $5a + $3c.

b)No, she cannot buy 2 adult tickets and 7 child tickets.

<h3>Define equation.</h3>

Mathematical equations are relationships between two expressions that are equal on both sides of the equal to sign. An equation is, for instance, 3y = 16.

Given,

Maymont Middle School is selling tickets for the winter musical. Adult tickets cost $5 each and child tickets cost $3 each.

a) Mathematical equation:

represents the total cost, t, for a adult tickets and c child tickets

t = $5a + $3c

A mathematical equation that represents the total cost, t, for a adult tickets and c child tickets is t = $5a + $3c.

b) Ciera has $28.

a = 2 c = 7

Equating values in equation,

= $5(2) + $3(7)

= $10 + $27

= $37

No, she cannot buy 2 adult tickets and 7 child tickets.

To learn more about equation, visit:

brainly.com/question/10413253

#SPJ1

4 0

1 year ago

whats 12+12-12-12-12-12-12-12-12-12-21-21-21-21-21-212-12-12-21-2334-2-23-3-3-3-3-33+1802301728727498729479274732947923749237498

tino4ka555 [31]

Answer:

1.8023017e+44

Step-by-step explanation:

I hope you understand I had to convert to simplify it.

7 0

3 years ago

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⚠️⚠️ emergency help ⚠️⚠️

stira [4]

Answer:

so, the equation of the line shown is y=2x-1

if the equation you are trying to write has a y-intercept of 4, the equation would be y=2x+4

Hope that helps ya!

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3 years ago