They will be forming a right triangle.
long leg is the height of Lyra. 22 meters high from the entrance.
short leg is the distance of Donna. 50 meters from the entrance.
We need to solve for the hypotenuse or the range of communication.
a² + b² = c²
22² + 50² = c²
484 + 2500 = c²
2,984 = c²
√2,984 = √c²
54.63 = c
The range of communication for the two radios is 55 meters.
.25x-log=y is inversely proportional to this
Answer:
Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
Step-by-step explanation:
Feets of fencing = 14
Perimeter = 14
Let x = Length y = width
Perimeter = 2(x + y)
For x = 1
2(1 + y) = 14
1 + y = 7
y =6
Area of rectangle ; x *y = 1 * 6 = 6 ft²
For x = 2
2(2 + y) = 14
2 + y = 7
y = 5
Area of rectangle ; x *y = 2 * 5 = 10 ft²
For x = 3
2(3 + y) = 14
3 + y = 7
y =4
Area of rectangle ; x *y = 3 * 4 = 12 ft²
For x = 4
2(1 + y) = 14
4 + y = 7
y = 3
Area of rectangle ; x *y = 4 * 3 =12 ft²
Hence, Area of rectangle possible. : 6ft² ; 10 ft², 12 ft²
Answer:
A. 220 miles
Step-by-step explanation:
You can multiply to find the answer. 5.5 times 40 = 220 miles.
Equilateral triangle. because all sides are equal.
