The probability that the transistor will last between 12 and 24 weeks is 0.424
X= lifetime of the transistor in weeks E(X)= 24 weeks
O,= 12 weeks
The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.
X~gamma(
)
E(X)=
=
=6 weeks
V(x)=
=24/6= 4
Now we can find the solutions:
The excel formula used to create Figure one is as follows:
=gammadist(X,
,
, False)
P(
)
P(
)
P(
)
P= 0.424
Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424
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Answer:

Step-by-step explanation:
the 6th power of 10 would be 10^6, then you'd multiply it by 3 which would make it 10^6*3
you could then simplify it and say 10^18 (multiply the exponents [6 and 3])
John is 31 and Jenny is 26

Negative multiply negative = Positive
Negative multiply positive = negative

Thus the answer is -4a + 16b - 12c - 12d.