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myrzilka [38]
3 years ago
11

Enter the numbers that goes in the boxes.

Mathematics
1 answer:
sergey [27]3 years ago
6 0

Answer:

A'(-1,4)

B'(-4,3)

C'(-2,1)

You might be interested in
Evaluate each logarithm. Do not use a calculator. Log (125)(1/25)
svetlana [45]

Answer:

-2/3

Step-by-step explanation:

Log125(1/25)=x

Raise each side to the base of 125

125^Log125(1/25)=125^x

1/25 = 125^x

Rewrite 25 as a power of 5  and 125 as a power of 5

1 / 5^2 = 5^3^x

The if power is in the denominator, we can bring it to the numerator by making it negative

5^-2 = 5^3^x

We know that a^b^c = a^(b*c)

5^-2 = 5^(3*x)

Since the bases are the same, the exponents are the same

-2 = 3x

Divide by 3

-2/3 = 3x/3

-2/3 =x

6 0
3 years ago
Can you please help me?
iren2701 [21]

Answer:

1 = 3

2 = 6

3 = 9

Step-by-step explanation:

for every # it is multiplied by 3 (ex. 7 • 3 = 21, 8 • 3 = 24, ect.)

therefore if it is multiplied by 3 each time

then 1 • 3 = 3

2 • 3 = 6

and 3 • 3 = 9

hope this helps :)

5 0
3 years ago
Read 2 more answers
Find m<br> A. 46<br> B. 23<br> C. 69<br> D. 167
Step2247 [10]

Answer:

69, nice

Step-by-step explanation:

118-49=69

3 0
3 years ago
Read 2 more answers
Newton’s law of cooling states that dx/dt= −k(x − A) where x is the temperature, t is time, A is the ambient temperature, and k
Vadim26 [7]

Answer:

(a) The solution to the differential equation is x = A_0Coswt + Ce^(-kx)

(b) The initial condition t > 0 will not make much of a difference.

Step-by-step explanation:

Given the differential equation

dx/dt= −k(x − A); t > 0, A = A_0Coswt

(a) To solve the differential equation, first separate the variables.

dx/(x - A) = -kdt

Integrating both sides, we have

ln(x - A) = -kt + c

x - A = Ce^(-kt) (Where C = ce^(-kt))

x = A + Ce^(-kx)

Now, we put A = A_0Coswt

x = A_0Coswt + Ce^(-kx) (Where C is constant.)

And we have the solution.

(b) Since temperature t ≠ 0, the initial condition t > 0 will not make much of a difference because, Cos(wt) = Cos(-wt).

It is not any different from when t < 0.

7 0
3 years ago
The product of a number and 9, increased by 4, is 58. Find the number.
diamong [38]
9x + 4 = 58
9x = 54
x = 6

The number is 6.
4 0
3 years ago
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