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myrzilka [38]
3 years ago
11

Enter the numbers that goes in the boxes.

Mathematics
1 answer:
sergey [27]3 years ago
6 0

Answer:

A'(-1,4)

B'(-4,3)

C'(-2,1)

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25-20x+4x² heh help pls and hurry :((
yulyashka [42]
25- 20x + 4x^2
=4x^2 - 20x + 25
=4x^2 - x(10+10) +25
=4x^2 - 10x - 10x + 25
=2x(2x - 5) - 5( 2x - 5)
=(2x - 5)(2x - 5)
=(2x - 5)^2
6 0
3 years ago
Read 2 more answers
Dy/dx= y^4 and y(2)= -1. Y(-1)=
cupoosta [38]

It looks like you're asked to find the value of y(-1) given its implicit derivative,

\dfrac{dy}{dx} = y^4

and with initial condition y(2) = -1.


The differential equation is separable:

\dfrac{dy}{y^4} = dx

Integrate both sides:

\displaystyle \int \frac{dy}{y^4} = \int dx

-\dfrac1{3y^3} = x + C

Solve for y :

\dfrac1{3y^3} = -x + C

3y^3 = \dfrac1{-x+C} = -\dfrac1{x + C}

y^3 = -\dfrac1{3x+C}

y = -\dfrac1{\sqrt[3]{3x+C}}

Use the initial condition to solve for C :

y(2) = -1 \implies -1 = -\dfrac1{\sqrt[3]{3\times2+C}} \implies C = -5

Then the particular solution to the differential equation is

y(x) = -\dfrac1{\sqrt[3]{3x-5}}

and so

y(-1) = -\dfrac1{\sqrt[3]{3\times(-1)-5}} = \boxed{\dfrac12}

6 0
2 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
A 1 3/4 kg fish weighed 1 3/16 kg after it was cleaned. how much was the decreased in weight of the fish.​
joja [24]

Answer:

b) Excessive water or water in the root zone can decrease ... ¼ 1, 240kg/ha. Crop price ¼ Ya р Ю $/kg р. Ю ¼ 1,240 kg/ha 0.9 р Ю ¼ $1, 116. WC ¼ $/m3.

180 pages

Step-by-step explanation:

7 0
2 years ago
Help please I would appreciate it ! 10 points
Helen [10]

Answer:

B and d

Step-by-step explanation:

b and d

3 0
3 years ago
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