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2 years ago

A vacuum tube that contains a grid can be classified as a A. rectifier B. triode C. pentode D. diode

Computers and Technology

1 answer:

Sedaia [141]2 years ago

7 0

Answer:

The correct answer is triode.

Explanation:

A vacuum tube is a device that control the flow of electric current between its electrodes in the presence of vacuum. The first vacuum tube which was used have two electrodes and called diode. Then another vacuum tube was invented having a grid between its two electrodes anode and cathode. So, that grid control the flow of electric current between these two electrodes. So, this tube named as triode named as it have one grid and anode and cathode. Other tubes which have more than one grid called according to there number of electrodes totally like tetrode, pentode.

I hope it will help you!

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nordsb [41]

Using the computational language C++ it is possible to write a code is possible to create a function that stores items like this:

<h3>Writting the code in C++: </h3>

//Header files

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

//Class inventoryItem

class inventoryItem

{

public:

//Variable declaration

string itemName;

string itemNumber;

double itemPrice;

int itemQuantity;

};

//implementation of menuItems() function.

void menuItems()

{

// Display the Menu

cout << "=============================\n";

cout << " 1) Add an item to memory\n"

<< " 2) Search memory for an item \n"

<< " 3) List what's in memory\n"

<< " 4) Total value on hand\n"

<< " 5) Save to a file\n"

<< " 6) Read from a file\n"

<< " 0) Exit Program" << endl;

}

//main method.

int main()

{

//variable declaration.

int mnuChoice, cn = 0, d;

string n;

double sum = 0, c;

int temp;

string a, b;

string inputBuffer;

inventoryItem items[100];

ifstream inventoryFile("inventory.txt");

if (inventoryFile)

{

//store the data from the file to memory.

while (!(inventoryFile.eof()))

{

inventoryFile >> items[cn].itemName;

inventoryFile >> items[cn].itemNumber;

inventoryFile >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

}

inventoryFile.close();

ifstream inventoryFile("inventory.txt");

ofstream fout;

fout.open("inventory.txt");

do

{

menuItems();

cout << cn << " items stored." << endl;

// Prompt and read choice form the user

cout << "Enter your choice: ";

cin >> mnuChoice;

switch (mnuChoice)

{

//Add a new inventory item to the data in memory.

case 1:

// Prompt and read name of the item from the user

cout << "Enter name of the item: ";

cin >> inputBuffer;

items[cn].itemName = inputBuffer;

// Prompt and read itemNumber from the user

cout << "Enter the itemNumber: ";

cin >> inputBuffer;

items[cn].itemNumber = inputBuffer;

// Prompt and read itemPrice from the user

cout << "Enter the itemPrice: ";

cin >> inputBuffer;

items[cn].itemPrice = atof(inputBuffer.c_str());

// Prompt and read itemQuantity from the user

cout << "Enter the itemQuantity: ";

cin >> inputBuffer;

items[cn].itemQuantity = atoi(inputBuffer.c_str());

cn++;

break;

//Search the inventory for an item by inventory number.

case 2:

temp = 0;

cout << "Enter inventory itemNumber: ";

cin >> n;

for (int i = 0; i < cn&&temp != 1; i++)

{

// If found, print the stored info

if (items[i].itemNumber.compare(n) == 0)

{

// Display the stored information

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

cout << items[i].itemName << "\t " << items[i].itemNumber << " \t" << items[i].itemPrice << "\t " << items[i].itemQuantity << endl;

temp = 1;

}

// otherwise print 'not found'.

if (temp == 0)

{

cout << "Not found!!!" << endl;

}

break;

//List the inventory on the screen

case 3:

cout << "The data in the memory is:" << endl;

cout << "Item Name" << "\t" << "Item Number" << "\t" << " Item Price" << "\t" << " Item Quantity" << endl;

for (int i = 0; i < cn; i++)

{

cout << items[i].itemName << "\t " << items[i].itemNumber << "\t " << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Calculate the total value on hand.

case 4:

for (int i = 0; i < cn; i++)

{

// The sum is the accumulation of all the (quantities * prices).

sum += items[i].itemPrice*items[i].itemQuantity;

}

cout << "sum value on hand: " << sum << endl;

break;

// Save the inventory data in the given file

case 5:

for (int i = 0; i < cn; i++)

{

if (i == cn - 1)

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity;

}

else

{

fout << items[i].itemName << " \t" << items[i].itemNumber << " \t" << items[i].itemPrice << " \t" << items[i].itemQuantity << endl;

}

break;

// Read the data from the file

case 6:

while (!(inventoryFile.eof()))

{

inventoryFile >> a;

inventoryFile >> b;

inventoryFile >> inputBuffer;

c = atof(inputBuffer.c_str());

inventoryFile >> inputBuffer;

d = atoi(inputBuffer.c_str());

// Dsiplays the data in the file

cout << a << " " <

}

break;

}

// Check the menu choice is not equal to 0,

//if it is equal exit from the loop

} while (mnuChoice != 0);

// File closed

fout.close();

inventoryFile.close();

}

// If the inventory file does not exist

// and then display the error message.

else

{

cout << "File does not exist!" << endl;

}

return 0;

}

See more about C++ code at brainly.com/question/17544466

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5 0

1 year ago