100 is what percent of 1000

You want to obtain a sample to estimate a population mean. Based on previous evidence, you believe the population standard devia

gtnhenbr [62]

Answer:

$n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547$

So the answer for this case would be n=22547 rounded up to the nearest integer

Step-by-step explanation:

Let's define some notation

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=58.2$ represent the population standard deviation

n represent the sample size

$ME =1$ represent the margin of error desire

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =+1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 99% of confidence interval now can be founded using the normal distribution. The significance would be $\alpha=0.01$ and the critical value $z_{\alpha/2}=2.58$ , replacing into formula (b) we got:

$n=(\frac{2.58(58.2)}{1})^2 =22546.82 \approx 22547$

So the answer for this case would be n=22547 rounded up to the nearest integer

3 0

3 years ago

Waitresses all want to work the "high roller" room at a local restaurant. There are six waitresses each evening assigned to one

Stells [14]

Answer:

The expected amount earned by a waitress per evening is $95.83.

Step-by-step explanation:

At a local restaurant there are six rooms total; 1 is a "high roller" room and other 5 are normal rooms.

There are 6 waitresses working at the local restaurant.

The room assignments are made by fair random selection such that each waitress has an equal probability of being in the "high roller" room.

This implies that a waitress can be assigned any of the six rooms with probability, $\frac{1}{6}$ .

The tip earned by the waitress working in the "high roller" room is $200 and that for other rooms is $75.

So, the distribution of tips earned is as follows:

X: $200 $75 $75 $75 $75 $75

P (X): $\frac{1}{6}$ $\frac{1}{6}$ $\frac{1}{6}$ $\frac{1}{6}$ $\frac{1}{6}$ $\frac{1}{6}$

The expected value of a random variable is given by:

$E(X)=\sum x\cdot P (X)$

Compute the expected amount earned by a waitress per evening as follows:

$E(X)=\sum x\cdot P (X)$

$=(200\times \frac{1}{6})+(75\times \frac{5}{6})\\\\=\frac{575}{6}\\\\=95.8333\\\\\approx 95.83$

Thus, the expected amount earned by a waitress per evening is $95.83.

3 0

3 years ago

What is one half as a decimal

iVinArrow [24]

One half as a decimal is .5

7 0

3 years ago

Read 2 more answers

What is the measure of 0 in radians? In the diagram, 0 is a central angle.

zloy xaker [14]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

There are 6 rental cars available for 18 riders, each holding either 2 or 4 riders. how many rental cars hold exactly 2 riders?

Tema [17]

Answer:

Cars for 2 riders are 3

Step-by-step explanation:

I. When total riders is 18

4(3) = 12 => Cars for 4 riders

2(3) = 6 => Cars for 2 riders

Got more question or something to discuss, leave comment below

8 0

3 years ago