Let quarters = q and
Dimes = d
We have 741 coins total so q + d = 741
Since quarters are 25 cents and Dimes are 10 cents then
25q + 10d = 10725 cents
Now we have 2 equations that we can solve using addition or substitution.
Using addition, first multiply the first equation by -10
-10 (q+d) = 741 (-10)
-10q - 10d = -7410
Now add the equations together
(-10q -10d = -7410)
+ (25q + 10d =10725)
________________
15q = 3315
q = 3315 / 15
q = 221
this is the number of quarters
Now plug this back into the original equation
q + d = 741
221 + d = 741
d = 741 - 221
d = 520
There are 520 dimes
Answer:
3n=2.49
Step-by-step explanation:
Answer: Your classmate incorrectly identified the sides that are proportional in the side-splitter theorem.
In this theorem, the segments formed on the traversal are proportional. However, in the diagram your friend is trying to prove that segments on the parallel lines are proportional. If he wanted to do that, he would need to have a different plan.
7 + 14
7(1 + 2)
44 - 11
11( 4 - 1)
18 - 12
6(3 - 2)
70 + 95
5(14 + 19)
60 - 36
12(5 - 3)
100 - 80
20(5 - 4)
Answer:
sdf67566655 so x is 129
Step-by-step explanation:
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