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natta225 [31]
3 years ago
7

State the null and alternative hypotheses for the statistical test described below. Your answer should be an expression composed

of symbols: Testing to see if there is evidence that a proportion is greater than 0.3.
H0: ____ vs Ha: ______
Mathematics
1 answer:
Artyom0805 [142]3 years ago
5 0

Answer:

Null hypothesis: p \leq 0.3

Alternative hypothesis: p>0.3

Step-by-step explanation:

For this question we need to take in count that the the claim that they want to test is "if the proportion is greater than 0.3". Our parameter of interest for this case is p and the estimator for this parameter is given by this statistic \hat p obtained from the info of sa sample obtained.

The sample proportion would be given by:

\hat p = \frac{X}{n}

Where X represent the success and n the sample size selected

The alternative hypothesis on this case would be specified by the claim and the complement would be the null hypothesis. Based on this the system of hypothesis for this case are:

Null hypothesis: p \leq 0.3

Alternative hypothesis: p>0.3

And in order to check the hypothesis we can use the one sample z test for a proportion with the following statistic:

z = \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}

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For a certain​ candy, 20​% of the pieces are​ yellow, 5​% are​ red, 5​% are​ blue, 10​% are​ green, and the rest are brown. ​a)
artcher [175]

Answer:

A) i) the probability it is brown = 60%.  (ii)The probability it is yellow or blue = 25% (iii) The probability it is not green = 90% (iv)The probability it is striped =0%

B) i)The probability they are all brown = 21.6%.  (ii) Probability the third one is the first one that is​ red = 4.51% (iii) Probability none are yellow = 51.2% (iv) Probability at least one is green = 27.1%

Step-by-step explanation:

A) The probability that it is brown is the percentage of brown we have.  However, Brown is not listed, so we subtract what we are given from 100%. Thus;

100 - (20 + 5 + 5 + 10) = 100 - (40) = 60%. 

The probability that one drawn is yellow or blue would be the two percentages added together:  20% + 5% = 25%. 

The probability that it is not green would be the percentage of green subtracted from 100:  100% - 10% = 90%. 

Since there are no striped candies listed, the probability is 0%.

B) Due to the fact that we have an infinite supply of candy, we will treat these as independent events. 

Probability of all 3 being brown is found by taking the probability that one is brown and multiplying it 3 times. Thus;

The percentage of brown candy is 60% from earlier. Thus probability of all 3 being brown is;

0.6 x 0.6 x 0.6 = 0.216 = 21.6%

To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100% - 5% = 95% = 0.95

Now, for the first two and the probability that it is red = 5% = 0.05

Thus for the last being first one to be red = 0.95 x 0.95 x 0.05 = 0.0451 = 4.51%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100 - 20 = 80%=0.80, to the third power:

0.80³ = 0.512 = 51.2%.

The probability that at least one is green is; 1 - (probability of no green). 

We first find the probability that all three are NOT green:

0.90³ = 0.729

1 - 0.729 = 0.271 = 27.1%.

3 0
4 years ago
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