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RideAnS [48]
3 years ago
8

Kane spent $89 on a camera, $235 on a DVD player, and

Mathematics
1 answer:
mamaluj [8]3 years ago
5 0

Answer:

400

Step-by-step explanation:just use caculater

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Solve the system of equations below by graphing.
Katen [24]

(0.5, 1.3) is the correct answer

Step-by-step explanation:

Given equations are:

y = 4x-0.8\ \ \ Eqn1\\2x+y-2.3=0\ \ \ Eqn2

As we can see that the given equations are linear equations which are graphed as straight lines on graph. The solution of two equations is the point of their intersection on the graph.

We can plot the graph of both equations using any online or desktop graphing tool.

We have used "Desmos" online graphing calculator to plot the graph of two lines (Picture Attached)

We can see from the graph that the lines intersect at: (0.517, 1.267)

Rounding off both coordinates of point of intersection to nearest tenth we get

(0.5, 1.3)

Hence,

(0.5, 1.3) is the correct answer

Keywords: Linear equations, variables

Learn more about linear equations at:

  • brainly.com/question/4228574
  • brainly.com/question/4168505

#LearnwithBrainly

8 0
4 years ago
Read 2 more answers
What is the centimeters?
S_A_V [24]
The answer is 11.6 centimeters.
3 0
3 years ago
Y = 2x + 3 find f(0)
vichka [17]

If y=2x+1 then that means f(x)=2x+3 and when you plug in x=0 you get f(0)=2\cdot0+3=\boxed{3}.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
What is the value of h
Marta_Voda [28]
I believe it would be 0 fr
8 0
3 years ago
A computer company produces an extremely light laptop and they claim it is the lightest on the market weighing only 32 ounces. t
Darina [25.2K]

Solution: We are given:

\mu=0.33,  \sigma =0.7

Let x be the weight (oz) of laptop

We have to find P(x>32)

To find the this probability, we need to find the z score value.

The z score is given below:

z=\frac{x-\mu}{\sigma}

       =\frac{32-33}{0.7}

       =-1.43

Now, we have to find P(z>-1.43)

Using the standard normal table, we have:

P(z>-1.43)=0.9236

0.9236 or 92.36% of laptops are overweight

       


4 0
3 years ago
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