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Schach [20]
3 years ago
8

Is this answer correct

Mathematics
1 answer:
Kobotan [32]3 years ago
6 0
Yes, that looks right.
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Suppose a parabola has an axis of symmetry at x = -8 , a maximum height of 2, and passes through the point (-7, -1). Write the e
lidiya [134]
As it has a maximum value the coefficient of x^2 will be negative

The vertex will be at (-8,2)  so in vertex form it is

y = a(x + 8)^2 + 2
and as it passes through (-7,-1) we have:

-1  = a(-7+8)^2 + 2

-1 = a + 2  so a = -3

answer is  y = -3(x + 8)^2 + 2

in standard form this is y = -3x^2 -48x  - 190
3 0
3 years ago
find the number 15 balls consisting of 5 black, 5 blue nd 5 white balls from a box which has 6 black, 7 blue and 8 white balls (
AleksAgata [21]

Answer:

Step-by-step explanation:

A bag contains 4 blue, 5 white, and 6 green balls. ... There are 5 red and 15 black balls in a box, two are picked up at random

4 0
3 years ago
How many times can 5 go into 78
creativ13 [48]

Answer:

15.6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
PLEASE help me with this question! This is really urgent! No nonsense answers please.
ipn [44]

Answer:

The second table of values.

Step-by-step explanation:

Let's put the x-values in the second table of values in correct number order:

x: -3, -2, -1, 0, 1

Now, let's write out the y-values in correct number order:

y: 1/4, 1, 4, 16, 64

Finally, let's rewrite the second table of values with the x-values in order and the corresponding y-values underneathe:

x: -3,  -2,  -1  0  1

y: 64,  16,  4, 1,  1/4

As it can be seen, as the x-values get bigger in value, the y-values get smaller exponentially, which is the definition of exponential decay.

6 0
3 years ago
use the given conditions to write an equation for the line in point slope form passing through (-5,7) and (-8,6)
KengaRu [80]
Point slope form is
y-y1=m(x-x1)
where slope=m
and (x1,y1) is a given point

slope=(y2-y1)/(x2-x1)
slope=(6-7)/(-8-(-5))=-1/(-8+5)=-1/-3=1/3

pick any point
(x,y)
(-5,7)

y-7=1/3(x+5) or
y-6=1/3(x+8)
5 0
3 years ago
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