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3 years ago

Plzzz helppp will mark brainlest stpps plzz if possible

Mathematics

1 answer:

VMariaS [17]3 years ago

8 0

Answer:

Step-by-step explanation:

Law of sines

$\frac{Sin A}{a}$ = $\frac{Sin B}{b}$

A and B are angles.

a and b are sides opposite corresponding angles.

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What amount of a 40% acid solution must be mixed with 200 mL 10% solution to produce a 20% solution?

vaieri [72.5K]

Answer:

Step-by-step explanation:

(x + 200)20 = 200(10) + x(40)

20x + 4000 = 2000 + 40x

2000 = 20x

X = 100 mL

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2 years ago

Write a division equation with a answer of 42,What is one I could write???

mrs_skeptik [129]

You could say 84/2, 126/3, or even 168/4

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3 years ago

Which expressions are equivelent to 3 1/4 - (-5/8)

sertanlavr [38]

Answer:

<em>Fraction form=31/8 Decimal form=3.875 </em>

Step-by-step explanation:

<em>Convert the mixed numbers to improper fractions, then find the Least common denominator and combine</em>

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3 years ago

What is the value of x?

Nikitich [7]

(x + 1)·(x + 1 + 11) = (x + 4)·(x + 4 + 1) --> x = 2

Tools like "photomath" are able to help you solving such equations.

7 0

3 years ago

There are 2,000 eligible voters in a precinct. A total of 500 voters are randomly selected and asked whether they plan to vote f

Ann [662]

Answer:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

The estimated population proportion for this case is:

$\hat p = \frac{350}{500}=0.7$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 99% confidence interval the value of $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=2.58$

And replacing into the confidence interval formula we got:

$0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647$

$0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753$

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

7 0

2 years ago