Answer:
9/2 if n goes to infinity and that the 2n^3 is under the whole expression
Step-by-step explanation:
Let me clear this .
find limit (9n^3 + 5*n - 2)/ (2n^3)
as n --> infinity
Did I put the parentheses in the right spot?
because if you leave it the way you did, then the whole expression goes to positive infinity as n goes to infinity But I will do this with parentheses
so
find limit (9n^3 + 5*n - 2)/ (2n^3)
simplify expression
limit (9/2) + 5/(2n^2) - 1/(n^3)
= (9/2) + 0 - 0
= (9/2)
Given;
6Ln (x + 2.8) = 9.6
We will transpose 6 in the Ln, so that we will leave Ln alone.
Ln (x + 2.8) = 9.6/6 = 1.6
we divide the 9.6 to 6 and we get 1.6
x + 2.8 = e^1.6
e^ for the substitution of Ln
x = e^1.6 - 2.8
insert the e^(1.6) in the calculator and you will get 4.95303242439511 and subtract 2.8 and you will get the answer.
x = 2.153
2.153 is the final answer in this question.
Answer:
Step-by-step explanation:
ok the first box is linear
the 2nd isnt
the 3rd isnt either
the fourth is
not sure about 5th but im sure it isnt
Hello there.
<span>There are 24 pizzas. each person gets 1/3 of a pizza. how many people can be fed from the 24 pizzas?
Answer: There are 3 thirds in a whole.
Therefore 3 people could be fed by 1 pizza.
Since there are 24 , multiply 3 by 24.
3 x 24 = 72.
The number of people that could be fed from the 24 pizzas is 72.
Hope This Helps You!
Good Luck Studying ^-^</span>
Answer:
B. 200 doses
Step-by-step explanation:
Given,
1 dose is required for 100 mg,
Since, 1 mg = 0.001 g,
⇒ 100 mg = 0.1 g
⇒ 1 dost is required for 0.1 g,
Thus, the ratio of doses and quantity ( in gram ) is 
Let x be the doses required for 20 grams,
So, the ratio of doses and quantity is 
Hence, 200 doses can be obtained from 20 grams of the drug.
Option 'B' is correct.
