We have points (-3, 4), (-1, 2), (4, -3) and (6,-5)
Let's verify it's a line by calculating the slopes between successive points.
Slope is change in y over change in x.
(2 - 4)/(-1 - -3) = -2/2 = -1
(-3 - 2)/(4 - -1) = -5/5 = -1
(-5 - -3)/(6 - 4) = -2/2 =-1
Yup. We have a line of slope -1 through point (-1, 2)
y - 2 = -1(x - -1)
y = -x - 1 + 2
y = -x + 1
That's the linear equation for the table.
Answer: Linear equation: y = -x + 1 slope = -1
The complete question is: Henry knows that the circumference of a circle is
18π inches. What is the area of the circle?
Solution:Circumference (C) of the circle can be written as:

Using this value of radius, we can find the Area(A) of the circle.
Therefore, area of the circle having a circumference of 18π inches will be 81π inches²
To simplify this, you would have to turn b^-2 into a positive exponent.
To do this, we have to flip b^-2, which would get rid of the negate from the exponent: -2
3a^4 b^-2 c^3 / b^-2
Then we get the answer:
3a^4 c^3
------------
b^-2
I have a picture to clarify!
I hope this helped, let me know if you don't understand! ^.^
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in