First, let’s find the area of the larger square. We know that the smaller square extend out 2ft and is2ft up. Well take these measures, and subtract the 2ft from the 12 ft at the top, and get 10ft, then add the 2ft to the left side, and find that it’s 6ft. We have these measures: 6ft 6ft 10ft 10ft for the larger rectangle. Let’s find the area. The are formula for a rectangle is Base(10ft) times height(6ft) . Thus 60ftsqrd. Next, let’s do the smaller rectangle. We do the same formula, 4 times 2, and get 8ftsqrd, add them together: 60ft + 8ft = 68ft!
Answer:
a. The critcal points are at

b. Then,
is a maximum and
is a minimum
c. The absolute minimum is at
and the absolute maximum is at 
Step-by-step explanation:
(a)
Remember that you need to find the points where

Therefore you have to solve this equation.

From that equation you can factor out
and you would get

And from that you would have
, so
.
And you would also have
.
You can factor that equation as 
Therefore
.
So the critcal points are at

b.
Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

Then,
is a maximum and
is a minimum
c.
The absolute minimum is at
and the absolute maximum is at 
Answer:
N < 6 or N
-7 or N > 12
Hope this helps. <em>lmk</em>.
Answer
y= 4
Step-by-step explanation:
6x-7y=22
6x(-1)-7y=22
-6-7y=22
-7y=22+6
-7y=28
y=-4