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katrin [286]
4 years ago
14

PLEASE HELP ASAP!!!!!!!

Mathematics
1 answer:
liraira [26]4 years ago
6 0

Answer:

C. The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.

Step-by-step explanation:

If t=3 or t=6 take the 3 and replace it for t. d(3)= 4.9(3)^2= 44.1 so with that answered you can now narrow the answer down to A. and C. so if we go back to the question the coin was dropped from the top of a building that then narrows it down to C.

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Determine the projection of vector w onto vector u. u=9i-6j, v=-3i-2j, w=19i+15j
Naily [24]

Answer:

proj_uw=6.2i-4.2j

Step-by-step explanation:

The projection of a vector v onto a vector u is defined as the projection of the vector v on the line that contains the vector u. It can be calculated  using the following formula:

proj_uv=\frac{u\cdot v}{||u||^2} u

Where:

u\cdot v

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and:

||u||

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||u||=\sqrt{u_1^2+u_2^2+...+u_n^2}

In this sense, the projection of vector w onto vector u is:

proj_uw=\frac{u\cdot w}{||u||^2} u

Where the dot product between u and w is:

u\cdot w =(9*19)+(-6*15)=171-90=81

And the magnitude of u is:

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Thus:

proj_uw=\frac{u\cdot w}{||u||^2} u=\frac{81}{117} \langle9,-6\rangle=\langle6.23,-4.15\rangle\approx6.2i-4.2j

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3 years ago
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<u>Dada la siguiente información:</u>

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Step-by-step explanation:

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