The 3rd and 7th terms of an arithmetic progression are 6and 30 respectively determine the common difference, first term,10th ter
2 answers:
Answer:
d = 6 , a₁ = - 6 and a₁₀ = 48
Step-by-step explanation:
The nth term of an arithmetic progression is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₃ = 6 and a₇ = 30 , then
a₁ + 2d = 6 → (1)
a₁ + 6d = 30 → (2)
Subtract (2) from (1) term by term to eliminate a₁
4d = 24 ( divide both sides by 4 )
d = 6
Substitute d = 6 into (1)
a₁ + 2(6) = 6
a₁ + 12 = 6 ( subtract 12 from both sides )
a₁ = - 6
Then
a₁₀ = - 6 + (9 × 6) = - 6 + 54 = 48
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