Answer:
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
Step-by-step explanation:
f(x) = sin (tan^-1 (ln(x)))
u substitution
d/du (sin u) * du /dx
cos (u) * du/dx
Let u =(tan^-1 (ln(x))) du/dx =d/dx (tan^-1 (ln(x)))
v substitution
Let v = ln x dv/dx = 1/x
d/dv (tan ^-1 v) dv/dx
1/( v^2+1) * dv/dx
=1/(ln^2x +1) * 1/x
Substituting this back in for du/dx
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
We know that cos (tan^-1 (a)) = 1/ sqrt(1+a^2)
cos (tan^-1 (ln(x)) * 1/(ln^2x +1) * 1/x
1/ sqrt(1+ln^2(x)) * 1/(ln^2x +1) * 1/x
The answer is expressions D, E, and G.
In algebra, a ‘term’ usually means the different parts of an expression that are separated by + and - signs.
Options A and B only have 1 term, an x or y³, so these are incorrect.
Option C has 1 term as well, ‘xyz’, because they are all multiplied together which makes it one term.
D and E both have 3 terms each, but F has 4 unique terms so this is incorrect also.
G has 3 unique terms, x³, x^4, and 7x, so this is correct.
When H is expanded, you will end up with more than 3 unique terms, so this is incorrect.
I hope this helps!
Answer:
4/4 quarters
Step-by-step explanation:
hope this will help you
Answer:
1.5 hours
Step-by-step explanation:
All you do is divide the speed by the distance 12/8=1.5 simple as that
Would be amazing if you marked me brainliest :)