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d1i1m1o1n [39]
3 years ago
8

Is 6 + 0 = 6 The addition inverse postulate or the The additive identity postulate

Mathematics
2 answers:
AysviL [449]3 years ago
6 0
Its the additive identity prosulate
Oduvanchick [21]3 years ago
4 0
Its the additive identity of postulate
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Which ordered pair is a solution of the equation?<br> -4r +7= 2y - 3
Mars2501 [29]

Answer:

y=-8, r= 2. this is your answer

6 0
4 years ago
Please answer<br><br>(7*2)^3=?
olga55 [171]
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7 0
3 years ago
What is the square root of 144?
Andrews [41]

Answer:

12, -12

Step-by-step explanation:

sqrt(144)

What number times itself = 144


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6 0
3 years ago
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What is the y -value of the solution to the system of equations shown? 6x=3y−24 4x+5y=−2
Vlada [557]

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8 0
2 years ago
Find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.
leonid [27]

<u>Answer-</u>

The equations of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit are

12x-5y+14=0 \\ 12x-5y-14=0

<u>Solution-</u>

Let a point which is 1 unit away from the line 12x-5y-1=0 is (h, k)

The applying the distance formula,

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{12^2+5^2}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{\sqrt{169}} \right |=1

\Rightarrow \left | \frac{12h-5k-1}{13} \right |=1

\Rightarrow 12h-5k-1=\pm 13

\Rightarrow 12h-5k=\pm 14

\Rightarrow 12h-5k=14,\ 12h-5k=-14

\Rightarrow 12h-5k-14=0,\ 12h-5k+14=0

\Rightarrow 12x-5y-14=0,\ 12x-5y+14=0

Two equations are formed because one will be upper from the the given line and other will be below it.

4 0
3 years ago
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