Divide 1 km in the ratio of 3:2. What is the smaller distance? Explain how to do this please

G)Find the the coefficient of y^5 in the expansion of (3+2y)^6

hodyreva [135]

Answer:

2

Step-by-step explanation:

A coefficient is a number of times a variable. So in this equation. 2 is being multiplied by y. so 2 is the coefficient.

3 0

2 years ago

Find the value of the six trig functions given the triangle below.

Y_Kistochka [10]

$\text{Here,}\\\\\text{Opposite side,}~ O = 2\\\\\text{Hypotenuse,}~ H = \sqrt 5 \\\\\text{Adjacent side,}~ A = \sqrt{5-4} = \sqrt 1 =1 ~~ ;[\text{By using Pythagorean theorem}]\\\\\\\sin \theta = \dfrac{O}H = \dfrac 2{\sqrt 5}\\\\\\\cos \theta = \dfrac{A}{H} = \dfrac{1}{\sqrt 5} \\ \\\\ \tan \theta = \dfrac{O}{A} = \dfrac 21 = 2$

$csc \theta = \dfrac{1}{\sin \theta} = \dfrac{\sqrt 5}2\\\\\\\sec \theta = \dfrac{1}{\cos \theta} = \sqrt 5 \\\\\\\cot \theta = \dfrac 1{\tan \theta} = \dfrac 12$

5 0

2 years ago

Please help, its urgent. (Question Below)

rusak2 [61]

The highest common factor of the numbers 210 and 308 is 4.

<h3>What is the highest common factor?</h3>

The highest factor of the two numbers which divides both the numbers is called as greatest common factor or HCF.

The highest common factor will be calculated by finding the factors of the two numbers. The factors of the two numbers are as follows:-

308 = 2 x 2 x 7 x 11

210 = 2 x 2 x 3 x 17

We can see that the 2 x 2 = 4 is the highest factor which is common between the two numbers 210 and 308. So 4 is the HCF which can divide both the numbers 210 and 308.

Therefore the highest common factor of the numbers 210 and 308 is 4.

To know more about HCF follow

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4 0

1 year ago

Natalie's aunt gave her $47 to spend on clothes at the mall. She bought 4 shirts that cost $4 each and a pair of pants that cost

Murljashka [212]

Answer:$18

Step-by-step explanation:4 * 4 = $16. One pair of pants = $13. 16 + 13 = $29. 47 - 29 = $18

5 0

3 years ago

Researchers studying starfish collected two independent random samples of 40 starfish. One sample came from an ocean area in the

krek1111 [17]

Answer:

The test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

H₀: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ = p₂.

Hₐ: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ ≠ p₂.

The two-proportion z-test would be used to perform the test.

A sample of n = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of the 40 starfish from the south, 11 were found to be over 8 inches in length.

Compute the sample proportion of starfish from north that were over 8 inches in length as follows:

$\hat p_{n}=\frac{6}{40}=0.15$

Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

$\hat p_{s}=\frac{11}{40}=0.275$

The test statistic is:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

Compute the combined proportion P as follows:

$P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125$

Compute the test statistic value as follows:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

$=\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$

Thus, the test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

8 0

3 years ago