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Harman [31]
3 years ago
15

Solve 2(x-1) = 10

Mathematics
2 answers:
strojnjashka [21]3 years ago
8 0
You first want to get rid of 2, so you divide two on both sides canceling the two on the left and getting x-1=5. then you add 1 to both sides getting x=6. Hope this helps!
dedylja [7]3 years ago
4 0
1) Distribute the 2 to x and -1. You get: 2x - 2 = 10

2) Add 2 to both sides of the equation. You get:
2x = 12

3 Divide both sides by 2.
You get: x = 6
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Please help I’ll make you the brainiest
antiseptic1488 [7]

Answer:

m=1 or m=-3

Step-by-step explanation:

when m=1,

(1+1)sq+1=5

4+1=5

5=5

True statement

when m=-3,

(-3+1)sq+1=5

(2)sq+1=5

4+1=5

5=5

True statement

6 0
3 years ago
7. A shopkeeper buys 300 identical articles a tota
sashaice [31]

Step-by-step explanation and answers:

300 articles at a total cost of $1500:

        $1500 / 300 = $5 / article

Sells 260 articles at a price 20% above this ^ price:

         20% of $5 is $1,   so $5 + $1 = $6

               Then he sells 260 articles at the price of ^ $6

               260 * $6 = $1560

Each of the remaining articles is sold at a price that's 50% of the 260 he sold.

         He sold those for $6,  so he would now sell the last 40 for $3

               From the remaining 40 articles, he makes 40 * $3, or $120

The shopkeeper made $1560 + $120 = $1680,  which is $180 more than he bought them for ($1500)

Therefore, he made a profit percentage of $180 / $1500,  (the amount of profit over the amount spent).

He made a profit percentage, compared to the cost price, of 12%.

3 0
3 years ago
Find the length of the variable .
ira [324]
DONT CLICK THE LINK!!!

THEY WILL FIND YOU ADDRESS

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5 0
3 years ago
The average human body contains about 40 L of water. What is the total amount of water contained in the 6.4 billion people in th
vesna_86 [32]

Answer:

2.56 * 10^11 L

Step-by-step explanation:

1 body has 40 L

Thus, the amount in 6.4 billion would be;

40 * 6.4 * 10^9

= 256 * 10^9

= 2.56 * 10^2 * 10^9

= 2.56 * 10^11 L

7 0
3 years ago
The half-life of a certain radioactive material is 83 hours. An initial amount of the material has a mass of 67 kg. Write an exp
Anvisha [2.4K]

Answer:

  • Initial amount of the material is 67 kg
  • Hal-life is 83 hours

<u>The required equation is:</u>

  • m(x) = 67 * (1/2)^{x/83}, where m- remaining amount of the radioactive material, x - number of hours

<u>After 5 hours the material remains:</u>

  • m(5) = 67 * (1/2)^{5/83} = 64.260 (rounded)
4 0
3 years ago
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