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lbvjy [14]
3 years ago
11

Image a coordinate plane with points plotted at ordered pairs Q(-4,4) R(2,4) S(5,-3) T(2,-3) and U (-4,-3) what is the area of t

he polygon QRSTU
Mathematics
1 answer:
pogonyaev3 years ago
8 0

In counterclockwise order that's


R(2,4), Q(-4,4), U(-4,3), T(2,-3), S(5,-3)


That's a trapezoid, height 7 upper base 6, lower base 9, so average base 15/2 and area 7(15)/2 = 105/2 = 52.5.


Answer: 52.5


The shoelace theorem gives the answer without thinking. We write the list on top of itself shifted and add up the cross produces:


R(2,4), Q(-4,4), U(-4,-3), T(2,-3), S(5,-3)

Q(-4,4), U(-4,-3), T(2,-3), S(5,-3), R(2,4),


A = \frac 1 2 | 2(4)-(4)(-4) + -4(-3)-(-4)(4) + -4(-3)- -3(2) + 2(-3)-(-3)(5) + 5(4)- -3(2)| = \frac{105}{2} \quad\checkmark




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