What is the sequence of second differences for ax +b?

Mathematics

1 answer:

MAVERICK [17]3 years ago

4 0

Answer:

ZERO

Step-by-step explanation

Write the given function as

F(x) = ax + b

i.e Y = ax + b

now differentiate Y with respect to X

dY/dX = d (ax + b)/ dx

dY/dX = a

now again differentiate this function with respect to x

so, d^2Y/dX^2 = d^2 (a)/dX^2

= 0 (ZERO)

note: differentiation of constant function is zero

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Given that f(x)= 2x+1 and g(x)= x^2 +2x+1 find (F+g)(2). Find (F.g)(x) find f(x)/g find f(2) +g(-2)?

Pepsi [2]

Answer:

$(f+g)(2) = 14$

$f(g(x)) = 2x^2 + 4x +3$

$\frac{f(x)}{g(x)} = \frac{2x+1}{x^2+2x+1}$

$f(2) + g(-2) = 6$

Step-by-step explanation:

Function composition and transformation combines functions together using operations such as addition, subtraction, multiplication, division and substitution. To find each, perform the operation with the functions f(x) = 2x+1 and $g(x) = x^2 + 2x +1$ .

(f+g)(x) is the functions f and g added together with 2 substituted for x.

$(f+g)(x) = 2x+1 + x^2 +2x + 1 = x^2 + 4x + 2\\(f+g)(2) = 2^2 + 4(2) + 2 = 14$

(f·g)(x) is function composition that means f(g(x)) or substitute g(x) into f(x).

$f(g(x)) = 2(x^2+2x+1)+1 = 2x^2 + 4x+2 + 1\\f(g(x)) = 2x^2 + 4x +3$

f(x) / g(x) is division of the two functions. Division can only occur with polynomials if they share the same factors or things which multiply to create them. If none are present, do not simplify.

$\frac{f(x)}{g(x)} = \frac{2x+1}{x^2+2x+1}$

This cannot be simplified.

f(2) + g(-2) means find the function value of f at 2 and the function value of g at -2 then add them together.

$f(2)+g(-2) = 2(2)+1 + ((-2)^2+2(-2) + 1)\\f(2) + g(-2) = 5 + (4-4+1)\\f(2) + g(-2) = 5 +1 = 6$