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2 years ago

Find b such that the points A(2,b),B(5,5)and C(-6,0) are the vertices of right angled with angle < BAC = 90 degree.

Mathematics

2 answers:

kipiarov [429]2 years ago

7 0

The <BAC angle isn't a perfect right angle because the image was a photo

If this helped, please consider picking this answer as the Brainliest Answer. Thank you!

Inessa05 [86]2 years ago

7 0

Answer:

b = -3 or b = 8

Step-by-step explanation:

We know that the perpendicular lines have negative-reciprocal slopes.

In other words, their product is - 1.

Find the slopes of AB and AC:

m(AB) = (5 - b)/(5 - 2) = (5 - b) / 3
m(AC) = (0 - b)/(- 6 - 2) = - b / - 8 = b/8

Find the the product of slopes and solve for b:

(5 - b)/3 * b/8 = - 1
b(b - 5)/24 = 1
b(b - 5) = 24
b² - 5b - 24 = 0
b² - 8b + 3b - 24 = 0
b(b - 8) + 3(b - 8) = 0
(b + 3)(b - 8) = 0
b = - 3 or b = 8

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Find b such that the points A(2,b),B(5,5)and C(-6,0) are the vertices of right angled ￼ with angle < BAC = 90 degree.​

Find b such that the points A(2,b),B(5,5)and C(-6,0) are the vertices of right angled with angle < BAC = 90 degree.