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Answer:
3
Step-by-step explanation:
Given the data: 7 6 5 9 3 4 7 9 5 8
INTERQUARTILE RANGE (IQR) = Q3 - Q1
Rearranging the data: 3, 4, 5, 5, 6, 7, 7, 8, 9, 9
Q3 = 0.75(n+1)th term
Q3 = 0.75(10 + 1) th term
Q3 = 0.75(11)th term = 8.25th term
Taking the 8th term = 8
Q1 = 0.25(11)th term = 2.75th
Taking the average of the 8th and 9th term:
(5 + 5) / 2 = 10/2 = 5
Q3 - Q1 = (8 - 5) = 3
4.5{4_x}+36=202-2.5{3+28}
you first multiply 4.5 and the numbers in the bracket.
4.5*4=18
4.5*x=4.5x
you will obtain 18-4.5x=202_2.5{3+28}
2.5*3=7.5 2.5*28=70
18_4.5x=202_7.5_70
18_4.5x=124.5_18
-4.5x=106.5
x=23.67
Hey there!
3 + 67 = 70,
so your answer will be:
x = 3
Hope this helps!
Have a great day (:
Answer:
a_n = 2^(n - 1) 3^(3 - n)
Step-by-step explanation:
9,6,4,8/3,…
a1 = 3^2
a2 = 3 * 2
a3 = 2^2
As we can see, the 3 ^x is decreasing and the 2^ y is increasing
We need to play with the exponent in terms of n
Lets look at the exponent for the base of 2
a1 = 3^2 2^0
a2 = 3^1 2^1
a3 = 3^ 0 2^2
an = 3^ 2^(n-1)
I picked n-1 because that is where it starts 0
n = 1 (1-1) =0
n=2 (2-1) =1
n=3 (3-1) =2
Now we need to figure out the exponent for the 3 base
I will pick (3-n)
n =1 (3-1) =2
n =2 (3-2) =1
n=3 (3-3) =0
