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aivan3 [116]
3 years ago
5

For which of the values of a and b is the following statement not true?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0
A B D are all false and C is true
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A 5-gallon jug of cleaning solution contains 6% bleach. How much pure water should be added to it to dilute to 4% bleach?
mihalych1998 [28]
Let's bear in mind that 5 gallons with a solution of 6% bleach, contains some water plus some bleach, how much bleach?  well, is just 6% of 5 gallons or namely (6/100) * 5 gallons, or 0.30 gallons.

if we use "x" gallons of water, well pure water has no bleach, so is 0% bleach, and it has a (0/100) * x or 0x gallons of bleach.

the mixture will be say "y" gallons, and is 4% bleach, so (4/100) * y is 0.04y gallons in the mixture of bleach.

\bf \begin{array}{lcccl}
&\stackrel{gallons}{quantity}&\stackrel{\textit{\% of bleach}}{amount}&\stackrel{\textit{gallons of bleach}}{amount}\\
&------&------&------\\
\textit{pure water}&x&0.00&0x\\
\textit{6\% solution}&5&0.06&0.3\\
-----&------&------&------\\
mixture&y&0.04&0.04y
\end{array}
\\\\\\
\begin{cases}
x+5=\boxed{y}\\
0x+0.3=0.04y\\
---------\\
0.3=0.04\left( \boxed{x+5} \right)
\end{cases}
\\\\\\
0.3=0.04x+0.2\implies 0.1=0.04x\implies \cfrac{0.1}{0.04}=x\implies 2.5=x
3 0
3 years ago
A bicycle tire is 28 inches in diameter.Approximately how far does the bicycle move forward each time the wheel goes around?(use
Debora [2.8K]

Answer:

88 Inches

Step-by-step explanation:

For any bicycle tire of a given diameter, the approximate distance moved by the bicycle each time the wheel goes around is determined by the circumference of the circular wheel.

Since the diameter =28 Inches

Circumference =\pi d =\frac{22}{7}X28 =88$ Inches

The bicycle moves 88 Inches forward each time the wheel goes around.

4 0
3 years ago
Does anyone know this? Needed ASAP
anzhelika [568]

Answer:

50 square units

Step-by-step explanation:

Using the formula provided, a = \frac{1}{2}h(b_1+b_2), substituting the height (5), b1 (8) and b2 (12), we can solve for the formula.

a = \frac{1}{2}\cdot5(8+12)\\\\a = \frac{1}{2}\cdot5(20)\\\\a = \frac{1}{2}100\\\\a = 50

Hope this helped!

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