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4 years ago

10

Why a square must be a rectangle, but a rectangle does not have to be a square?

1 answer:

Dmitry_Shevchenko [17]4 years ago

7 0

A square has four sides and they all have to be of equal length with each corner forming a 90 degree angle. A rectangle is also 4 sided but it's sides don't have to be of equal length

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I don't know how to do anything. I basically need help with everything

lutik1710 [3]

Okay,

Radius, is half of the diameter.
Diameter, is the line that splits the circle in half.

1). R=50 D=100
2). R=10 D=20
3). R=5 D=10
4). R=29 D=58
5). R=11 D=22
6). R=31.5 D=63
7). R=45 D=90
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4 years ago

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What is the vertex of f(x)=x2−8x+15 ?

mr_godi [17]

Answer:

(4,-1)

i strongly believe that is the answer, pls mark as brainlist

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3 years ago

Given equations A and B as 2/5x+y=12 and 5/2y-x=6 respectively which expression will eliminate the variable X a) 5/2A+2/5B b)5/2

frutty [35]

Answer:

C) $A+\frac{2}{5}B$

Step-by-step explanation:

Given Equations:

A) $\frac{2}{5}x+y=12$

B) $\frac{5}{2}y-x=6$

In order to eliminate $x$ we need to multiply $\frac{2}{5}$ to equation B and add it to A.

Multiplying $\frac{2}{5}$ to B.

⇒ $\frac{2}{5}\times (\frac{5}{2}y-x)=\frac{2}{5}\times 6$

⇒ $(\frac{2}{5}\times\frac{5}{2}y)-(\frac{2}{5}x)=\frac{12}{5}$

⇒ $y-\frac{2}{5}x=\frac{12}{5}$

Adding it equation A.

$\frac{2}{5}x+y=12$

+ $-\frac{2}{5}x+y=\frac{12}{5}$

We get $2y=\frac{72}{5}$

Thus $x$ is eliminated.

So, the expression used to eliminate $x$ is:

$A+\frac{2}{5}B$

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3 years ago

Solve the Equation for y . 9x +5y = -2

ASHA 777 [7]

Answer:

$\large\boxed{y=\dfrac{-9x-2}{5}}$

Step-by-step explanation:

$9x+5y=-2\qquad\text{subtract}\ 9x\ \text{from both sides}\\\\5y=-9x-2\qquad\text{divide both sides by 5}\\\\y=\dfrac{-9x-2}{5}$

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3 years ago

Convert 75 miles per hour to feet per minute.

ra1l [238]

6600 Feet per minute

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3 years ago

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