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marin [14]
3 years ago
8

What fraction is closer to 0.125 1/2 , 1/4 , 1/8 , 1/10

Mathematics
1 answer:
S_A_V [24]3 years ago
5 0
1\8 is actually 0.125 so I hope this helps  
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Which is true of a population in a statistical survey?​
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The population of a statistical survey is chose at random, so it's not believed to be biased.

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3 years ago
Researchers would like to test if the mean bone mineral density is different for the three different groups. Conduct an ANOVA te
laiz [17]

Answer:

<em>H</em>₀: <em>μ₁ = μ₂= μ₃</em>

<em>Hₐ: </em>At least one of the means is different.

Step-by-step explanation:

Analysis of variance or ANOVA test is used to determine whether the means of different groups are similar or not.

The hypothesis of an ANOVA test for <em>n</em> homogeneous groups is:

H_{0}: \mu_{1}= \mu_{2}= \mu_{3}...= \mu_{n}\\H_{a}: At\ least\ one\ of\ the\ means\ is\ different

In this case the researcher is testing whether the mean bone mineral density is different for the three different groups.

The hypothesis for this test can be defined as follows:

<em>H</em>₀: The mean bone mineral density is not different for the three different groups, i.e. <em>μ₁ = μ₂= μ₃</em>

<em>Hₐ: </em>The mean bone mineral density is different for the three different groups, i.e. at least one of the means is different.

3 0
3 years ago
G a survey of property owners' opinions about a street-widening project was taken to determine if owners' opinions were related
Naily [24]

Answer:

The expected frequency for people against the project and who have over 120 feet of property foot frontage is 3.9.

Step-by-step explanation:

The data provided is:

                                                   Opinion    

Front Footage   For       Undecided Against    Total

Under 45 feet    12                4              4              20

  45-120 feet           35                5             30      70

Over 120 feet     3                2              5              10

       Total           50                11             39    100

The formula to compute the expected frequency is:

E(X)=\frac{\text{Row Total}\times \text{Column Total}}{\text{TOTAL}}

Compute the expected frequency for people against the project and who have over 120 feet of property foot frontage as follows:

E(X)=\frac{\text{Row Total}\times \text{Column Total}}{\text{TOTAL}}

E(5)=\frac{10\times 39}{100}=\frac{39}{10}=3.9

Thus, the expected frequency for people against the project and who have over 120 feet of property foot frontage is 3.9.

6 0
3 years ago
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