2(3a+8) I used photo math, and it gave me a step by step. The top steps are factor the expressions (20a+4)-(14a-12), which is (4(5a+1)-2(7a-6)
Answer:
Probability that event will have both red marbles will be 2.3% or 0.023.
Step-by-step explanation:
Given:
Total red marbles=5
Total blue marbles=25
Total number of marbles =30
To Find:
The probability that both are red without replacement of marbles.
Solution:
Now
Total sample space is 30 and total red marbles are 5
For a event that getting red marble probability is ,
=Total red marbles /total marbles.
=5/30
=1/6
So probability if getting red marble is 1/6
<em>Now for second chance there will be 4 red marbles remaining and 29 total marbles so,</em>
In second chance probability if getting red marble will be
=total red marbles present/total marbles remaining
=4/29
Now ,
The required probability will be getting both at a time
i.e probability getting red AND red marble so here AND operator which means multiple both the probability.
Probability both will have red =1/6*4/29
=4/(29*6)=2/(29*3)
=0.022988
=0.023
=2.3 %
Well you need to find a common denominator which 30 is the closest one. 5/6 becomes 25/30, 9/10 becomes 27/30. 27/30+ 25/30 = 52/30. To simplify that you divide by 2 to get 26/15. It is no longer divisible to a whole number after that point.
Asymptote at x = 3 and a horizontal asymptote at y = 1. The curves approach these asymptotes but never cross them. The method used to find the horizontal asymptote changes depending on how the degrees of the polynomials in the numerator and denominator of the function compare.
36 perches altogether.
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