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3 years ago

12

I need help can anyone please help

1 answer:

ahrayia [7]3 years ago

4 0

Answer:

vertically opposite angle

Step-by-step explanation:

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explain how you can use structure to find the dicmal numbers that will be shown on the next four miles markers

Alisiya [41]

Ggggggggg you want me to do that for one thing and she will it your you will your life mother of I

7 0

3 years ago

Reason Can you subtract a positive integer from a positive integer

Afina-wow [57]

Answer:

No

Step-by-step explanation:

No matter the situation, when you multiply a negative by a negativeyou get a positive and a positive by a positive you get a positive. but if its two different like a negative and a positive then its NEGITIVE.

let's say you have 23 and you're multiplying by 2.

It's always increasing so it doesnt ever reach the negitive numbers.

6 0

3 years ago

Which of the lines graphed has a slope of -1/2 and a y-intercept of 3?

VARVARA [1.3K]

Answer:

The answer is image 3.

Step-by-step explanation:

The equation for the line will be y = (-1/2)x + 3 so the gradient is negative and you will have to find the x-intercept and y-intercept.

x-intercept :

$let \: y = 0$

$0 = - \frac{1}{2} x + 3$

$\frac{1}{2} x = 3$

$x = 3 \div \frac{1}{2}$

$x = 6$

y-intercept :

$let \: x = 0$

$y = - \frac{1}{2} (0) + 3$

$y = 3$

8 0

3 years ago

Read 2 more answers

Find the taylor polynomial t3(x) for the function f centered at the number

inysia [295]

Answer:

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

Step-by-step explanation:

We are given that

$f(x)=7tan^{-1}(x)$

a=1

$T_n(x)=\sum_{r=0}^{n}\frac{f^r(a)(x-a)^r}{r!}$

Substitute n=3 and a=1

$t_3(x)=f(1)+f'(1)(x-1)+\frac{f''(1)(x-1)^2}{2!}+\frac{f'''(1)(x-1)^3}{3!}$

$f(x)=7tan^{-1}(x)$

$f(1)=7tan^{-1}(1)=7\times \frac{\pi}{4}=\frac{7\pi}{4}$

Where $tan^{-1}(1)=\frac{\pi}{4}$

$f'(x)=\frac{7}{1+x^2}$

Using the formula

$\frac{d(tan^{-1}(x))}{dx}=\frac{1}{1+x^2}$

$f'(1)=\frac{7}{2}$

$f''(x)=\frac{-14x}{(1+x^2)^2}$

$f''(1)=-\frac{7}{2}$

$f''(x)=-14x(x^2+1)^{-2}$

$f'''(x)=-14((x^2+1)^{-2}-4x^2(x^2+1)^{-3}})$

By using the formula

$(uv)'=u'v+v'u$

$f'''(x)=-14(\frac{x^2+1-4x^2}{(1+x^2)^3}$

$f'''(x)=(-14)\frac{-3x^2+1}{(1+x^2)^3}$

$f'''(1)=-14(\frac{-3(1)+1}{2^3})=\frac{7}{2}$

Substitute the values

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{2\times 3\times 2\times 1}(x-1)^3$

$t_3(x)=\frac{7\pi}{4}+\frac{7}{2}(x-1)-\frac{7}{4}(x-1)^2+\frac{7}{12}(x-1)^3$

7 0

3 years ago

Using the linear combination method, what is the solution to the system of linear equations 7x-2y=-20 and

marissa [1.9K]

Answer:

7x -2y + 20 =0 and 9x + 4y + 6 =0 are the solutions to the answer

5 0

3 years ago