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posledela
4 years ago
9

A substance is on its fifth half-life. Which approximates the percentages of radioactive and stable isotopes, respectively? 96.9

%; 3.1% 3.1%; 96.9% 12.5%; 87.5% 87.5%; 12.5% Need an answer fast
Chemistry
1 answer:
garik1379 [7]4 years ago
5 0

Answer:

B

Explanation:

Edge 2020

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Unless I’m misreading “d”, it just seems like a more in-depth version of “a”. So it wouldn’t hurt to try that one.
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3 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. A(g)
wolverine [178]

Answer:

The correct answer is 8.10

Explanation:

Given:

A(g) + 2B(g) ↔ AB₂(g)   Kc = 59 ---- Eq. 1

A(g) + 3B(g) ↔ AB₃(g)   Kc = 478 ----- Eq. 2

We have to rearrange the chemical equations in order to obtain:

AB₂(g) + B(g) ↔ AB₃(g) Kc = ?

AB₂(g) is a reactant, so we have to use the reverse reaction of Eq. 1, in this case Kc= 1/59. Since AB₃(g) is a product, we use the forward reaction of Eq.2, and the constant is the same: Kc= 478.  The following is the sum of rearranged chemical equations, and the compounds in bold and italic are canceled:

 AB₂(g)       ↔   <em>A(g)</em> + <em>2B(g)</em>          Kc₁= 1/59

<em>A(g)</em> + <em>3B(g)</em> ↔   AB₃(g)                  Kc₂= 478

-----------------------------------------

AB₂(g) + B(g) ↔ AB₃(g)

If we add reactions at equilibrium, the equilibrium constants Kc are mutiplied as follows:

Kc = Kc₁ x Kc₂ = 1/59 x 478 = 478/59 = 8.10

The value of the missing equilibrium constant is 8.10.

6 0
3 years ago
One of the waste byproducts of a nuclear reactor using uranium-235 is strontium-90 with half-life of about 28 years. If we have
e-lub [12.9K]

Answer:

(a) 140 years

(b) 3.125 pounds

Explanation:

<u>QuestIons</u>

(a) How long is five half-life

(b)  How much radioactive strontium is left after five half-life

Given that:

Half-life is about 28 years; &

There are 100 pounds of this radioactive waste

Five half-life will be;

= 28 × 5

= 140 years

The amount of radioactive remaining after five half-life is:

= 100 \times( \dfrac{1}{2}) ^5

= 100 × 0.03125

= 3.125 pounds

5 0
3 years ago
What evidence of chemical reaction will be observed based on this chemical reaction?
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4 years ago
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