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3 years ago

Question 1: Gases diffuse easily through these types of solids

Chemistry

1 answer:

nexus9112 [7]3 years ago

3 0

Q1: Gases diffuse easily through amorphous or porous solids.

Q2:All changes in phase are called change in state of matter.

Answer:

Explanation:

Gases diffuse easily through amorphous or porous solids. Usually solids are densely packed with no space. But porous solids can help in diffuse gas into them. Due to the vacancy present in these solids, gas can easily diffuse through these types of solids.

Similarly, the phase changes lead to change in the state of matter. As the basic of change in phase leads to change in its state from solid to liquid or from liquid to gas or vice versa. So change in state of matter will occur in any change in phase.

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10 points Which of these is the best example of heat transfer by radiation? *

insens350 [35]

Answer:

a) A satellite is warmed by sunlight.

Explanation:

Heat transfer by radiation mostly involves heat gain or heat loss from the Sun. In this case, Option A is the only option where sunlight is involved so it is the best example of heat transfer by radiation.

3 0

3 years ago

Strong acids have a ______ value of Ka and the equlibrium for the reaction with water lies far to the _______.

nika2105 [10]

Answer:

All strong acids have a higher value of $K_{a}$ and the equilibrium for the reaction with water lies far to the right.

Explanation:

All strong acids dissociate completely in the solution. Higher the value of dissociation constant of the acid, higher will be the dissociation of the acid.

The reaction of the acid with water will be favored in the forward direction for acids having higher dissociation constant value ( $K_{a}$ ).

The dissociation of a strong acid say HA in water is shown below $\textrm{HA}\left ( aq \right )+\textrm{H}_{2}\textrm{O}\left ( l \right )\rightleftharpoons \textrm{A}^{-}\left ( aq \right )+\textrm{H}_{3}\textrm{O}^{+}\left ( aq \right )$

Higher the value of $K_{a}$ , more will be the dissociation of the acid in water. The reaction will move far to the right side.

4 0

3 years ago

The fuel used in many disposable lighters is liquid butane, C4H10. Butane has a molecular weight of 58.1 grams in one mole. How

BARSIC [14]

<h3>Answer:</h3>

6.21 × 10²² Carbon Atoms

<h3>Solution:</h3>

Data Given:

Mass of Butane (C₄H₁₀) = 1.50 g

M.Mass of Butane = 58.1 g.mol⁻¹

Step 1: Calculate Moles of Butane as,

Moles = Mass ÷ M.Mass

Putting values,

Moles = 1.50 g ÷ 58.1 g.mol⁻¹

Moles = 0.0258 mol

Step 2: Calculate number of Butane Molecules;

As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Butane Molecules can be written as,

Moles = Number of C₄H₁₀ Molecules ÷ 6.022 × 10²³ Molecules.mol⁻¹

Solving for Number of Butane molecules,

Number of C₄H₁₀ Molecules = Moles × 6.022 × 10²³ Molecules.mol⁻¹

Putting value of moles,

Number of C₄H₁₀ Molecules = 0.0258 mol × 6.022 × 10²³ Molecules.mol⁻¹

Number of C₄H₁₀ Molecules = 1.55 × 10²² C₄H₁₀ Molecules

Step 3: Calculate Number of Carbon Atoms:

As,

1 Molecule of C₄H₁₀ contains = 4 Atoms of Carbon

So,

1.55 × 10²² C₄H₁₀ Molecules will contain = X Atoms of Carbon

Solving for X,

X = (1.55 × 10²² C₄H₁₀ Molecules × 4 Atoms of Carbon) ÷ 1 Molecule of C₄H₁₀

X = 6.21 × 10²² Atoms of Carbon

5 0

4 years ago

Read 2 more answers

he solution is said to be an ideal solution, only when the intermolecular forces of attraction between A-A, B- B and A- B are ne

KengaRu [80]

Answer:True

Explanation:

A ideal solution is a solution which obeys Raoults law on almost every concentration and temperature range.

Ideal solutions are formed by mixing those solute and solvent which has identical molecular properties.

Lets take A be the solute and B be the solvent so to form a ideal solution from these components the solute-solute(A-A) molecular interaction and solvent -solvent (B-B) molecular interactions must be identical with the solute solvent interaction(A-B).

The solute-solute molecular interaction ,solute-solvent molecular interaction and solvent-solvent molecular interaction must be equal in order to form a ideal solution.

The enthalpy of mixing and volume of mixing of ideal solution is zero.

enthalpy of mixing is the amount of energy released on mixing a solute and solvent and in case of ideal solutions it is zero.

Volume of mixing is change in volume on mixing a solute and solvent.

3 0

4 years ago

List five compound in chemistry and their formula

enyata [817]

Answer:

Acetic acid CH3COOH

Hydrochloric acid HCl

Sulfuric acid H2SO4

Acetate CH3COO–

Ammonia

Explanation:

Hope i am right

8 0

3 years ago