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Sav [38]
3 years ago
13

Give the result of the following expression with the correct number of significant figures

Chemistry
1 answer:
Marianna [84]3 years ago
4 0
84 m/s x 31.221 s = 2600 m
-rounded from 2622.564 m because 84 m/s has only two significant figures
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Strike anywhere matches contain the compound tetraphosphorus trisulfide, which burns to form tetraphosphorus decaoxide and sulfu
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Answer:

194.6 mL of SO₂

Explanation:

The reaction that takes place is:

P₄S₃ + 6O₂(g) → P₄O₁₀ + 3SO₂(g)

<u>To solve this problem we need to use PV=nRT</u>, so first let's convert the given units:

  • 23.8 °C → 23.8 + 273.15 = 296.95 K
  • 747 torr → 747/760 = 0.983 atm

We need to calculate V, so in order to do that we calculate n, using the mass of the reactant (P₄S₃):

0.576 g P₄S₃ * \frac{1molP_{4}S_{3}}{220gP_{4}S_{3}} *\frac{3molSO_{2}}{1molP_{4}S_{3}} = 7.85 * 10⁻³ mol SO₂ = n

  • Now we calculate V:

PV=nRT

0.983 atm * V =  7.85 * 10⁻³ mol * 0.082 atm·L·mol⁻¹·K⁻¹ * 296.95 K

V = 0.1946 L

  • Finally we convert L into mL:

0.1946 * 1000 = 194.6 mL

8 0
3 years ago
A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
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ke prop to v^2


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The graph shows the volume of a gaseous product formed during two trials of a reaction. A different concentration of reactant wa
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A: Trial 1, because the average rate of the reaction is lower.

The rate of reaction is the speed with which reactants are converted into products. It is also the rate at which reactants disappear and products appear.  The higher the rate of reaction, the greater the amount of product formed in a reaction.

If we look at the graph, we will realize that trial 1 produces a lesser amount of product than trial 2. This implies that the  average rate of the reaction in trial 1 is lower than in trial 2.

Lower average rate of reaction implies lower concentration of the reactants since the rate of reaction depends on the concentration of reactants.

Hence trial 1 has a lower concentration of reactants because the average rate of the reaction is lower.

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