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Assoli18 [71]
3 years ago
5

How many halves are in 2/3

Mathematics
1 answer:
galina1969 [7]3 years ago
3 0

Answer:

1

Step-by-step explanation:

One half can only fit into 2/3 one time because because 1/2 plus one half is 1 whole. 2/3 is not one whole so 1/2 cannot go into it more than once.

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27. In a school of 500 students, 125 like chess and 160 like badminton. 45 students like chess and badminton both. Find how many
ozzi

Answer:

170

Step-by-step explanation:

Add 160 and 45 and 125

Then subtract it to the total number of students

So 500 minus 330

5 0
3 years ago
Can you help me please everyone is ignoring my questions
galben [10]

Answer:

A= 37 degrees

C= 43 degrees

Step-by-step explanation:

Hey there!

So this question looks a lot more complicated than it really is.

Complementary angles are the same.

Supplementary angles add up to 180 degrees or in other words a straight line.

If A and B are complementary and B equals 37 degrees, than A is also 37 degrees.

To find C, all we would do is subtract 37 from 180 to find the leftover amount.

180-37=43

So, in conclusion:

A= 37 degrees

C= 43 degrees

Hoped this helped! :D

Comment if you have any further questions!

3 0
3 years ago
Read 2 more answers
Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. W
dem82 [27]

Answer:

15 times 2 - 26 = x

Step-by-step explanation:

Warren drives half the distance Kendall drives to work. Kendall drives 26 more miles to work than Joe. Warren drives 15 miles. Write an equation that models this situation. Use x to represent the number of miles Joe drives to work.

W X 1/2 = K

K - 26 = J

so 15 times 2 - 26 = x

6 0
2 years ago
Read 2 more answers
Hello, I am currently very stuck with this problem and I am unsure as to how I would solve it.
borishaifa [10]

We have the equation

20y=x^2-10-15

Let's complete the square, to do it let's add and subtract 25 on the right side

\begin{gathered} 20y=x^2-10-15+25-25 \\  \\ 20y=(x-5)^2-15-25_{} \\  \\ 20y=(x-5)^2-40 \\  \\  \end{gathered}

Now we can have y in function of x

\begin{gathered} y=\frac{1}{20}(x-5)^2-2 \\  \\  \end{gathered}

Now we can already identify the vertex because it's in the vertex form:

y=a(x-h)+k

Where the vertex is

(h,k)

As we can see, h = 5 and k = -2, then the vertex is

(5,-2)

Now we can continue and find the focus, the focus is

\mleft(h,k+\frac{1}{4a}\mright)

We have a = 1/20, therefore

\begin{gathered} \mleft(5,-2+5\mright) \\  \\ (5,3) \end{gathered}

The focus is

(5,3)

And the last one, the directrix, it's

y=k-\frac{1}{4a}

Then

\begin{gathered} y=-2-5 \\  \\ y=-7 \end{gathered}

Hence the correct answer is: vertex (5, -2); focus (5, 3); directrix y = -7

5 0
1 year ago
In the diagram, △ABC∼△DEF. The area of △ABC is 180 square centimeters. Find the area of △DEF.
Alexeev081 [22]

Answer:

20

Step-by-step explanation:

The first step is to find out the similarity reason of the sides of the triangle, so we just divide the big side by the small side (12/4=3).

Now, for the similarity reason of the areas, we just square that number (3^2=9).

Then we just divide the area of the big triangle by 9, which is 180/9= 20.

4 0
2 years ago
Read 2 more answers
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