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3 years ago

2x2 - 4x –9 = 0 Completing the swuare

Mathematics

1 answer:

ASHA 777 [7]3 years ago

4 0

Step-by-step explanation:

$(a-b)^2=a^2-2ab+b^2\\\\2x^2-4x-9=0\qquad|\text{add 9 to both sides}\\\\2x^2-4x-9+9=0+9\\\\2x^2-4x=9\qquad|\text{divide both sides by 2}\\\\\dfrac{2x^2}{2}-\dfrac{4x}{2}=\dfrac{9}{2}\\\\x^2-2x=4.5\\\\x^2-2\cdot x\cdot1=4.5\qquad|\text{add}\ 1^2\ \text{to both sides}\\\\x^2-2\cdot x\cdot1+1^2=4.5+1^2\\\\(x-1)^2=5.5\iff x-1=\pm\sqrt{5.5}\qquad|\text{add 1 to both sides}\\\\x=1-\sqrt{5.5}\ \vee\ x=1+\sqrt{5.5}$

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Multiply: (x+y)by (x+y) a+b by a^2-b^2 (a+5) by (a^2-2a-3) (a^2-ab+b^3) by (a+b)

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Answer:

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Step-by-step explanation:

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3 years ago

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The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

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The braking distance at 55 mph, is approximately 298.35 ft.

The braking distance at 85 mph, is approximately 708.92 ft.

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a. The braking distance if the car is going 25 mph is therefore;

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At 25 mph, the braking distance is approximately 63.7 ft.

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At 55 mph, the braking distance is approximately 298.35 ft.

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The car was moving at v ≈ 98.211 ft./s

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