Let the width of the frame = x
Let the cost of a linear foot of the frame = y
Let the inside dimension of the length of the frame = a
Let the inside dimension of the width of the frame = b.
The total length of the frame = 2*a + 4x
The total width of the frame = 2b
The total amount of the frame in feet is (2a + 4x + 2b)*y = Cost
If this is incorrect please leave a message on my home page.
Height and then the inches over 12.
Ex. 5'4" = 5 4/12 or 5 1/3
Answer:
3rd option
Step-by-step explanation:
substitute x = f(x) into g(x)
g(f(x))
= g(x² + 2)
= 4(x² + 2) - 1
= 4x² + 8 - 1
= 4x² + 7
Substitution
-2x+8=x^2-9x+18
x^2-7x+10=0
Factoring, we get
(x-5)(x-2)=0
x=5, x=2
If x equals 5,
y=-2(5)+8=
-10+8=
-2
Therefore, we derive our first solution:
<h2><u><em>
x=5,</em></u></h2><h2><u><em>
y=-2</em></u></h2>
Now we solve for our second x
If x=2,
y=-4+8=
4
Therefore, we derive our second solution:
<h2><u><em>
x=2</em></u></h2><h2><u><em>
y=4</em></u></h2>
<u><em></em></u>
-Hunter
