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Amiraneli [1.4K]
3 years ago
7

Answer the following questions:

Mathematics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

d. \displaystyle [-1\frac{1}{2}π, 0], [-\frac{π}{2}, 0], [1\frac{1}{2}π, 0], [\frac{π}{2}, 0]

c. \displaystyle [0, 1]

b. \displaystyle Range: \\ Set-Builder\:Notation → y|1 ≥ y ≥ -1 \\ Interval\:Notation → [-1, 1]

a. Domain: \\ Set-Builder\:Notation → x|x ∈ R \\ Interval\:Notation → (-∞, ∞)

Step-by-step explanation:

This is the graph of \displaystyle y = cos\:x,in which its AMPLITUDE [<em>A</em>] ALWAYS starts ONE BLOCK ABOVE the <em>midline</em>. In the trigonometric formula below, −C gives the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:

\displaystyle y = Acos[Bx - C] + D

NOTE: Depending on how your trigonometric graphs are structured, your vertical shift [<em>D</em>] might tell you to space out the amplitude of the graphs alot more evenly on both ends.

<u>Extended Information on Trigonometric Graphs</u>

\displaystyle Vertical\:Shift = D \\ Phase\:Shift =      \frac{C}{B} \\ Period = \frac{2}{B}π \\ Amplitude = |A|

I am joyous to assist you anytime.

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