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2 years ago

If you add 17 to an even number, the answer will be even. OA. True OB. False

Mathematics

2 answers:

Paha777 [63]2 years ago

5 0

Answer:

Step-by-step explanation:

well, first you have to add the number to an even number 4+17=21

21 is not an even number 12+17=29 which is also an odd number

answer B is false.

Rama09 [41]2 years ago

4 0

Answer:

the answer is false because it will always be a odd number

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Help Please? cx<br> Find a measure of angle 8.

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3 years ago

How many $10$-digit numbers are there, such that the sum of the digits is divisible by $2$?

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Complete question is;

How many 10 - digit numbers are there, such that the sum of the digits is divisible by 2?

Answer:

There are 4500000000 ten digit numbers whose sum is divisible by 2.

Step-by-step explanation:

Since we are dealing with 10 digit numbers, the first 10 digit number whose sum is divisible by 2 is; 1000000001.

While the last 10 digit number whose sum is divisible by 2 is 9999999999.

Now,to find how many 10 digit numbers whose sum are divisible by 2, we will simply divide the difference of both numbers by 2 and then add 1 to the answer. This is because subtracting the minimum from the maximum gives us the number of 10 digit numbers we have. Then dividing by 2 gives the number of ten digit numbers with sum divisible by 2 in between. Then adding 1 to the result to cover the number not included gives;

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3 years ago

Miguel draws a square on a coordinate plane. One vertex is located at (5,4). The length of each side is 3 units. Circle the lett

Ulleksa [173]

Answer:

A, B, and E.

Step-by-step explanation:

We know that one vertex is at (5, 4), and each side of our square is 3 units long.

Then the distance between the known vertex and another vertex is 3 units (if those vertexes are connected by a side of the square) or (√2)*3 units (if those vertexes are connected by the diagonal of the square).

Also remember that the distance between two points (a, b) and (b, c) is:

distance = √( (a - c)^2 + (b - d)^2)

So we need to find the distance between our point and all the ones given in the options:

A) the distance between (5, 4) and (5, 1) is:

distance = √( (5 - 5)^2 + (4 - 1)^2) = 3

Then point (5, 1) can be a vertex.

B) The distance between (5, 4) and (5, 7) is:

distance = √( (5 - 5)^2 + (4 - 7)^2) = 3

Then (5, 7) can be a vertex.

C) The distance between (5, 4) and (7, 8) is:

distance = √( (5 - 7)^2 + (4 - 8)^2) = √( 2^2 + 4^2) = √20

Point (7, 8) can not be a vertex.

D) The distance between (5, 4) and (2, 6) is:

distance = √( (5 - 2)^2 + (4 - 6)^2) = √( 3^2 + 2^2) = √13

Point (2, 6) can not be a vertex.

E) The distance between (5, 4) and (2, 1) is:

distance = √( (5 - 2)^2 + (4 - 1)^2) = √( 3^2 + 3^2) = √18 = √(2*9) = √2*√9 = √2*3

Then point (2, 1) can be a vertex.

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3 years ago

A wooden log 10 meters long is leaning against a vertical wall with its other end on the ground. The top end of the log is slidi

Andre45 [30]

Answer:

Step-by-step explanation:

This is a related rates problem from calculus using implicit differentiation. The main equation is Pythagorean's Theorem. Basically, what we are looking for is $\frac{dx}{dt}$ when y = 6 and $\frac{dy}{dt}=-2$ .

The equation for Pythagorean's Theorem is

$x^2+y^2=c^2$ where x and y are the legs and c is the hypotenuse. The length of the hypotenuse is 10, so when we find the derivative of this function with respect to time, and using implicit differentiation, we get:

$2x\frac{dx}{dt}+2y\frac{dy}{dt}=0$ and divide everything by 2 to simplify:

$x\frac{dx}{dt}+y\frac{dy}{dt}=0$ . Looking at that equation, it looks like we need a value for x, y, $\frac{dx}{dt}$ and $\frac{dy}{dt}$ .

Since we are looking for $\frac{dx}{dt}$ , that can be our only unknown and everything else has to have a value. So what do we know?

If we construct a right triangle with 10 as the hypotenuse and use 6 for y, we can solve for x (which is the only unknown we have, actually). Using Pythagorean's Theorem to solve for x:

$x^2+6^2=10^2$ and